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andrezito [222]
3 years ago
10

What is 9 6/9 - 4 8/9

Mathematics
2 answers:
NeX [460]3 years ago
6 0
The answer is 4 7/9.

Since you cannot subtract the numerators, you have to take 1 from the whole number, so 9 turns into 8 and you add the denominator to the numerator to make the equation 8 15/9 - 4 8/9 which is 4 7/9 :).
lesantik [10]3 years ago
4 0
You already have a common denominator, so you should convert to improper fractions to subtract them easier. These would be 87/9-44/9, and then you subtract the numerators and leave the denominator. 87-44=43, so your answer is 43/9, or 4 7/9, or 4.77777...
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Anarel [89]

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6 0
3 years ago
What is the image of(8,12) after a dilation by a scale factor of 1/4 centered at the origin?
max2010maxim [7]
<h3>Answer:  (2, 3)</h3>

=================================================

Explanation:

1/4 = 0.25 is the scale factor

Multiply this with each coordinate of the given point

0.25*8 = 2 is the new x coordinate

0.25*12 = 3 is the new y coordinate

So (8,12) moves to (2,3) after applying the dilation

The scale factor k makes 0 < k < 1 true, so the point is closer to the origin after applying the dilation.

--------

Side note: this trick of multiplying the scale factor by each coordinate only works if the dilation is centered at the origin. For any other center, you'll need to apply a translation first, dilate, then translate back again.

3 0
3 years ago
8/15 divided by 1/3 reduce your answer
klio [65]
Here we can use fact than we can multiply fraction by inverse of fraction instead of dividing it.
Inverse of 1/3 is 3/1
Lets multiply it
\frac{8}{15}* \frac{3}{1}= \frac{24}{15}= \frac{24:3}{15:3}= \frac{8}{5}=1 \frac{3}{5} - its our result
7 0
3 years ago
How many 4 sided figures are in this diagram?
ser-zykov [4K]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
Erica collected a total of $180 for her favorite charity over the first 3 months of the year. She collected the same amount in t
ankoles [38]
X+x+3x= 180
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Your answer is D. $108
4 0
3 years ago
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