(1/5) / 4.5 = 2 / m....1/5 mile to 4.5 minutes = 2 miles to m minutes
cross multiply
(1/5)(m) = (2)(4.5)
1/5m = 9
m = 9 * 5/1
m = 45 minutes <===
Answer: The answer is x ≥ -10
Step-by-step explanation:
92 degrees
Triangle= 180 degrees
180-60-28= 92
:)
Let's move like a crab, backwards some.
after 2 years?

after 3 years?

is that enough to pay the $1100?
now, let's write 1000(1+r)² in standard form
1000( 1² + 2r + r²)
1000(1 + 2r + r²)
1000 + 2000r + 1000r²
1000r² + 2000r + 1000 <---- standard form.
Answer:
y =
x - 12
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = -
x ← is in slope- intercept form
with slope m = -
, c = 0
Given a line with slope m then the slope of a line perpendicular to it is
= -
= -
=
, then
y =
x + c ← is the partial equation
To find c substitute (3, - 8) into the partial equation
- 8 = 4 + c ⇒ c = - 8 - 4 = - 12
y =
x - 12 ← equation of perpendicular line