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Svet_ta [14]
3 years ago
11

Consider a binary-search method in an array that reports whether an object is in the array. The documentation indicates that the

caller must pass in a sorted array or the results are unspecified. According to strict design-by-contract, who is responsible for checking that the array is sorted
Computers and Technology
1 answer:
inn [45]3 years ago
5 0

#include<iostream.h>

#include<conio.h>

void sort(int A[], int N)

{int I,J,tmp;

for(I=0;I<N;I++)

{for(J=0;J<N;J++)

{if(A[J]>A[J+1])

{tmp=A[J];A[J]=A[J+1];A[J+1]=tmp;}}}}

void main()

{int a[15],I,n,l,u,sh,mid,k=0;

clrscr();

cout<<”Enter the array size”;

cin>>n;

l=0;u=n-1;

cout<<”\nEnter the array elements”<<endl;

for(i=0;i<n;i++)

cin>>a[i];

sort(a,n);

cout<<”\nEnter search element”;

cin>>sh;

cout<<”\nNow, applying N=Binary Search”<<endl;

while(l<=u)

{mid=(l+u)/2;

If(a[mid]>sh)

u=mid-1;

if(a[mid]<sh)

l=mid+1;

if(a[mid]==sh){k=1;break;}}

if(k==1)

cout<<”\n Element is present at “<<(mid+1)<<endl;

else

cout<<”\n Element not found”;

getch();

}

<u>Explanation:</u>

Binary Search is a type of search method which is more effective and takes more traversals than the linear search. It compares the each element to the middle element. If the element is found, it gives the position otherwise it will give no result.

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3 years ago
Write a program that takes in an integer in the range 20-98 as input. The output is a countdown starting from the integer, and s
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Answer:

// program in C++.

#include <bits/stdc++.h>

using namespace std;

int main() {

//  variable  

int num;

cout<<"Enter the number between 20 and 98: ";

// read number

cin >> num;

while(num<20||num>98)

{

   cout<<"Wrong input!!enter number between 20-98 only:";

   cin>>num;

}

cout<<"The output is: ";

while(num % 10 != num /10)

{

// print numbers.  

cout<<num<<" ";

// update num.

num--;

}

// display the number.

cout<<num<<endl;;

return 0;

}

Explanation:

Read a number from user and assign it to variable "num".Check if entered number  is in between 20-98 or not.If input number is less than 20 or greater than 98 then  ask again to enter a number between 20-98 until user enter a valid input.Then print  the countdown from input number till both the digit of number are same.

Output:

Enter the number between 20 and 98: 99                                                                                    

Wrong input!!enter number between 20-98 only:12                                                                            

Wrong input!!enter number between 20-98 only:93                                                                            

The output is: 93 92 91 90 89 88

Enter the number between 20 and 98: 77                                                                                    

The output is: 77

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