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Yuliya22 [10]
3 years ago
10

Half the difference of a number and 18 is equivalent to -25. find the number

Mathematics
1 answer:
KonstantinChe [14]3 years ago
3 0

Answer:

Hi there!

Your answer is:

the number is 68

Step-by-step explanation:

(18-n) /2 = -25

×2

(18-n) = -50

-18

-n = -68

/-1

n= 68

Plug it back in!

(18-68) /2 = -25 ???

-50/2 = -25 ✓✓✓

Hope this helps

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Answer: -4F and 3

Explanation: combine -F and -3F makes -4F and 14 - 11 = 3
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Please help meeee !!
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The fish population in a local lake is 10,000. The population increase by half every year. Which function represents the fish po
sweet-ann [11.9K]

Answer:

5. f(x) = 10,000 (1.5)^x

Step-by-step explanation:

We would have to multiply the original amount by 1.50^x because the initial amount would be 1, and 50% increase would be .5 so 1.5 and you raise it to the number of years to show the total increase.

Let's test it.

Initial:

10,000

After 1 year

10,000 + (.5*10000)

10,000 + 5000 = 15,000

After 2 years

15,000 + (.5*15000)

15,000 + 7500 = 22,500

Let's try our equation.

f(x) = 10,000 (1.5)^x

x = 2

10,000(1.5)^2

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The same!

7 0
3 years ago
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I don't understand how to do this,<br> 6x + 6/6 &gt; 1/3x + 2
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Answer:

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Please help!!!!
valentina_108 [34]
ANSWER

\frac{ {t}^{2}  + 4t - 12}{ {t}^{2} - 4 }  =  \frac{t  + 6}{ t + 2}
where,
t \ne - 2



EXPLANATION

We want to simplify the rational expression

\frac{ {t}^{2}  + 4t - 12}{ {t}^{2} - 4 }


We can observe that the numerator of the given rational expression is a quadratic trinomial and the denominator is a difference of two squares



We need to split the middle term in the numerator and rewrite the denominator as a difference of two squares to obtain,




\frac{ {t}^{2}  + 4t - 12}{ {t}^{2} - 4 }  =  \frac{{t}^{2}  + 6t - 2t - 12}{ {t}^{2}  -  {2}^{2} }



We now factor to obtain,

\frac{ {t}^{2}  + 4t - 12}{ {t}^{2} - 4 }  =  \frac{t (t+ 6) - 2(t  + 6)}{ (t  -  2)(t + 2)}


This implies that,

\frac{ {t}^{2}  + 4t - 12}{ {t}^{2} - 4 }  =  \frac{(t - 2) (t  + 6)}{ (t  -  2)(t + 2)}


We now cancel out common factors to obtain,

\frac{ {t}^{2}  + 4t - 12}{ {t}^{2} - 4 }  =  \frac{(t  + 6)}{ (t + 2)}


The restriction is that, the denominator cannot be zero.

Thus

t + 2 \ne0


This implies that,

t  \ne - 2
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3 years ago
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