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brilliants [131]
3 years ago
5

What was the distance of the ship from its starting point

Mathematics
1 answer:
tresset_1 [31]3 years ago
8 0
A^2+B^2=C^2
18^2+80^2=C^2
324+6400=C^2
6724=C^2
*Squareroot*
82=C
You might be interested in
How many times does 4 go into 56
Oduvanchick [21]
4 multiplied by 14 gives you 56 so its 14
7 0
3 years ago
Read 2 more answers
333 erasers cost \$4.41$4.41dollar sign, 4, point, 41. Which equation would help determine the cost of 444 erasers? Choose 1 ans
Rudiy27

Answer:

Option D will be correct.

Step-by-step explanation:

The 333 erasers cost $4.41.

We have to determine the cost of 444 erasers.

Let the price of 444 erasers is $x.

Therefore, since the number of erasers cost per dollars is constant, hence the equation that would help to determine the cost of 444 erasers will be \frac{333}{4.41} = \frac{444}{x}

⇒ \frac{3}{4.41} = \frac{4}{x}

Therefore, option D will be correct. (Answer)

6 0
3 years ago
The number of bags of mulch you need to cover a planting area varies jointly with the area to be mulched (a) in sq ft and the de
Lena [83]

Answer:

  22 2/9

Step-by-step explanation:

When z "varies jointly" with x and y, it can be described by the formula

   z = kxy

Here, we have bags of mulch (n) varying jointly with area (a) and depth (d), both in feet. The given information can let us find the value of k.

  n = kad

  10 = k·(120)(1/4)

  10/30 = k = 1/3 . . . . . divide by the coefficient of k

Now, we can fill in the other values of interest.

  n = (1/3)·(200)·(1/3) = 200/9

  n = 22 2/9

You need 22 2/9 bags of mulch to cover 200 ft² to a depth of 4 inches.

_____

<em>Comment on the problem</em>

This problem requires the formula be written with both area and depth expressed in feet, yet it gives depth in inches. The formula can also be written using depth in inches. In that case, k = 1/36.

8 0
2 years ago
Davis knows that the area of his square shaped bag is 81 ft squared. what is the length of any side of the bag?
LiRa [457]


area = l x w

area = 9 x 9

area =  81

Hope this was helpful. :-)



4 0
3 years ago
Read 2 more answers
Select the correct answer. What is the surface area of the victory podium shown here? Include all surfaces of the podium, includ
Leya [2.2K]

Answer:

Option C is correct.

Step-by-step explanation:

Given the dimension of the surfaces i.e length, width and height of podium. we have to calculate the surface area of the victory podium.

As Surface area of cuboid is 2(LW+WH+HL)

In the given figure, the upper cuboid has dimension

L=2.5 ft. , W=1.5 ft, H=1.5 ft

\text{Surface area=}2(2.5(1.5)+1.5(1.5)+1.5(2.5))=19.5ft^2

\text{Area of bottom face of upper cuboid=}L\timesW=2.5\times1.5=3.75ft^2

The upper face is occuring twice therefore it must be subtracted to find the area

Dimensions of lower podium are

L=7.5 ft. , W=1.5 ft, H=1.5 ft

\text{Surface area=}2(7.5(1.5)+1.5(1.5)+1.5(7.5))=49.5ft^2

Now, Surface area of podium included bottom is

19.5+49.5-3.75=65.25 square feet.

Hence, option C is correct.

4 0
3 years ago
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