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GarryVolchara [31]
3 years ago
12

Solve the following systems by substitution

Mathematics
1 answer:
Paladinen [302]3 years ago
8 0

Answer:

The answer to your question is below

Step-by-step explanation:

Question 1

                x = 5                       Equation l

                2x + y = 10              Equation ll

- Substitute Equation l in equation ll

               2(5) + y = 10

                y = 10 - 10

                y = 0

- Solution  (5, 0)

Question 2

                 x + 16y = 20          Equation l

                 x = 4y                    Equation ll

Substitute equation ll in equation l

                4y + 16y = 20

                        20y = 20

                           y = 20/20

                           y = 1

-Find x

                x = 4(1)

                x = 4

-Solution

                (4, 1)

Question 3

                   2x + 8y = 20            Equation l

                     x = 2                       Equation ll

-Substitute equation ll in equation l

                   2(2) + 8y = 20

                      4 + 8y = 20

                            8y = 20 - 4

                            8y = 16

                              y = 16/8

                              y = 2

- Solution

                   (2, 2)              

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kramer

Answer:

3/8 + 1/8

Step-by-step explanation:

so you just need to add the both firsnumber which is 3 and 1 is equal to 4 and second is you add the both second number whick is 8 and 8 is equal to 16 now that you got all the numbers needed to complete the fraction just put the 4 in the top and pu the slach or / and put the 16 in the bottom

Exact Answer:<em>4</em><em>/</em><em>1</em><em>6</em>

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Option A is correct.

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Step-by-step explanation:

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3 0
3 years ago
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