Answer:
see below
Step-by-step explanation:
a. Has a slope of 2 and passes through (10,17)
Using the slope intercept form
y = mx+b where m is the slope and b is the y intercept
y = 2x+b
Substitute the point into the equation
17 = 2(10)+b
17 = 20+b
Subtract 20 from each side
17-20 =b
-3 =b
y = 2x-3
b. passes through (1,-4) and (2,-5)
First find the slope
m= (y2-y1)/(x2-x1)
= (-5- -4)/(2-1)
= (-5+4)/(2-1)
= -1/1
= -1
Using the slope intercept form
y = -x+b
Substitute a point into the equation
-4 = -1(1) +b
-4 = -1+b
Add 1 to each side
-3 = b
y = -x+3
Answer:
(9.5, 0) is in quadrant I. (-4, 7) is in quadrant II. (-1, -8) is in quadrant III.
Step-by-step explanation:
The negative signs say everything (quite literally). If there are no negative signs, it is in quadrant I. If there is one in the x-axis (the first number in an ordered pair), it is in quadrant II. If there are 2 negative signs, it is in quadrant III, and if there is one in the y-axis (the second number in an ordered pair), it is in quadrant IV.
Answer is below in the picture:-
(From the problem, we know (triangle)ABC (round of equal of) (triangle)A'B'C'. So, <A'B'C' = <ABC {the properties of congruent triangles}. So, ray BC is the angle, bisector of angle ABA')
I hope it helps.
This is a differnce of 2 perfect squares
a²-b²=(a-b)(a+b)
so
9x²-64=(3x)²-(8)²=(3x-8)(3x+8)
factors are (3x-8) and (3x+8)
