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Lady bird [3.3K]

3 years ago

6

Jake had 2.95 mL of a liquid. He added more liquid and now has 3.56 mL. How many mL of liquid did Jake add? Enter your answer in

the box.

1 answer:

Anarel [89]3 years ago

7 0

0.61ml is the answer all u do is subtract.

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I can’t find the area can you please help me with it. It’s the question with the question mark

Romashka-Z-Leto [24]

Answer:

1947 units^2

Step-by-step explanation:

you can split it up into different sections of rectangles.

the first one is 25x39= 975

The second section is the connector which you do

43-25=18

and you do 39-27=12 and then

you multiple 18x12 which equals 216

and the final section you do 24+12=36

and 36x21=756

and finally you add them all up to equal 1947 units^2

6 0

3 years ago

Solve the inequality showing all steps needed to justify your answer. State your solution in interval notation

dybincka [34]

<span>Which two measures did the United States take to counter terrorism after the September 11 attacks?

</span>

5 0

3 years ago

Suppose 20 students delegates will attend the conference. Each school should be represented fairly in relation to it's populatio

algol [13]

Answer:

To find out the number coming from each school, you need to use the proportion of the school's population out of the population of all three.

Total population = 618 + 378 + 204

= 1,200 students

North Middle school:

= 618/1,200 * 20

= 10 students

Central Middle School:

= 378 / 1,200 * 20

= 6 students

South Middle School:

= 204/1,200 * 20

= 4 students

7 0

3 years ago

The Nuthouse offers a mixture of soy nuts and almonds, Almonds

elena55 [62]

Answer:

14 pounds

Step-by-step explanation:

The given equations can be solved for y by substituting for x. The first equation is convenient for writing x in terms of y.

<h3>Solution</h3>

x = 20 -y . . . . . . . subtract y from the first equation

7(20 -y) +5.5y = 119 . . . . . substitute for x in the second equation

140 -1.5y = 119 . . . . . . . . simplify

21 = 1.5y . . . . . . . . . . . add 1.5y -119 to both sides

14 = y . . . . . . . . . . . .divide by 1.5

14 pounds of soy nuts should be used in the mixture.

__

<em>Additional comment</em>

There are many ways to solve a system of two linear equations. The attachments shows a matrix solution using a suitable calculator. It tells us that x=6 and y=14, as we found above.

6 0

2 years ago

There are two games involving flipping a coin. In the first game you win a prize if you can throw between 45% and 55% heads. In

Nina [5.8K]

Answer:

d) 300 times for the first game and 30 times for the second

Step-by-step explanation:

We start by noting that the coin is fair and the flip of a coin has a probability of 0.5 of getting heads.

As the coin is flipped more than one time and calculated the proportion, we have to use the <em>sampling distribution of the sampling proportions</em>.

The mean and standard deviation of this sampling distribution is:

$\mu_p=p\\\\ \sigma_p=\sqrt{\dfrac{p(1-p)}{N}}$

We will perform an analyisis for the first game, where we win the game if the proportion is between 45% and 55%.

The probability of getting a proportion within this interval can be calculated as:

$P(0.45$

referring the z values to the z-score of the standard normal distirbution.

We can calculate this values of z as:

$z_H=\dfrac{p_H-\mu_p}{\sigma_p}=\dfrac{(p_H-p)}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_H-p)>0\\\\\\z_L=\dfrac{p_L-\mu_p}{\sigma_p}=\dfrac{p_L-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_L-p)$

If we take into account the z values, we notice that the interval increases with the number of trials, and so does the probability of getting a value within this interval.

With this information, our chances of winning increase with the number of trials. We prefer for this game the option of 300 games.

For the second game, we win if we get a proportion over 80%.

The probability of winning is:

$P(p>0.8)=P(z>z^*)$

The z value is calculated as before:

$z^*=\dfrac{p^*-\mu_p}{\sigma_p}=\dfrac{p^*-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p^*-p)>0$

As (p*-p)=0.8-0.5=0.3>0, the value z* increase with the number of trials (N).

If our chances of winnings depend on P(z>z*), they become lower as z* increases.

Then, we can conclude that our chances of winning decrease with the increase of the number of trials.

We prefer the option of 30 trials for this game.

8 0

3 years ago