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Setler79 [48]
3 years ago
5

The midpoint of AB

Mathematics
1 answer:
siniylev [52]3 years ago
6 0
This is step by step i think this is correct

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To earn a fitness award, your average heart rate while walking must be between 80 and 89 beats per minute, inclusive. Suppose yo
Morgarella [4.7K]
Based on the first three (3) recordings, your average heart rate in beats per minute is approximately 84 bpm (mean). Calculating for the standard deviation of the samples, we get about 2.5 bpm. To give the possible heart rates on the fourth, we may solve for the range:

Upper Range = Mean + Standard Deviation = 84 + 2.5 = 86.5 bpm or 87 bpm
Lower Range = Mean - Standard Deviation = 84 - 2.5 = 81.5 bpm or 82 bpm

Therefore the fourth and final recording will likely to fall in the range of 82 - 87 beats per minute. You will win the fitness award!

<em>ANSWER: 82-87 beats per minute</em>

3 0
4 years ago
Can someone help me with this thanks ​
Firdavs [7]

Answer:

<u><em>i ''Dont Know'' i need more detail on what Ur talking about </em></u>

Step-by-step explanation:

6 0
3 years ago
Our math team had m students last year, but this year it has already n students! By what percent did the number of students grow
lukranit [14]
Sinn is the total amount of students now and m were the students before, you subtract them both (n-m) and divide that by m. Then, since to get a percentage from a fraction you have to multiply by 100, your answer should look like this: n-m/m*100
4 0
3 years ago
Partition a line segment in the given ratio.
mestny [16]

Check the picture below.

\textit{internal division of a line segment using ratios} \\\\\\ T(-5,9)\qquad U(9,2)\qquad \qquad \stackrel{\textit{ratio from T to U}}{5:2} \\\\\\ \cfrac{T\underline{V}}{\underline{V} U} = \cfrac{5}{2}\implies \cfrac{T}{U} = \cfrac{5}{2}\implies 2T=5U\implies 2(-5,9)=5(9,2)

(\stackrel{x}{-10}~~,~~ \stackrel{y}{18})=(\stackrel{x}{45}~~,~~ \stackrel{y}{10}) \implies V=\underset{\textit{sum of the ratios}}{\left( \cfrac{\stackrel{\textit{sum of x's}}{-10 +45}}{5+2}~~,~~\cfrac{\stackrel{\textit{sum of y's}}{18 +10}}{5+2} \right)} \\\\\\ V=\left( \cfrac{ 35 }{ 7 }~~,~~\cfrac{ 28}{ 7 } \right)\implies {\Large \begin{array}{llll} V=(5~~,~~4) \end{array}}

4 0
1 year ago
Can someone help me with this please
Yuri [45]

Answer:

ofc ill help! x=-35

Step-by-step explanation:

4 0
3 years ago
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