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Ket [755]
3 years ago
6

True or false these answers are equivalent 1.6 , 1 and 3/5 , 160%

Mathematics
1 answer:
marysya [2.9K]3 years ago
6 0
True these are all equivalent.
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Roger gets $40 per day as wages and $4.50 as commission for every pair of shoes he sells in a day. His daily earnings goal is $1
Mila [183]

Answer:

40+4.50x+112

16 shoes daily to make his goal

Step-by-step explanation:

to find how much shoes he would have to sell take away 40 from both sides of the equation which would leave you with 4.50x=72 next divide 4.50 out of both sides of the equation x=16 so he would have to sell 16 pairs of shoes a day to meet his goal

3 0
3 years ago
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Two brothers, Kevin and Greg, each inherit S43000. Kevin invests his inheritance in a savings account with an annual return of 1
creativ13 [48]

Answer:

S1548.

Step-by-step explanation:

1-7% =- 0.017 and 5.3% - 0.053.

Kevin : After 1 year he has 43,000 * 0.017 = S731.

Greg:  After 1 year he has  43,000 * 0.053 =  S2279

Difference = 2279 - 731 = S1548.

4 0
3 years ago
A number multiplied by -7, subtracted drom the sum of 7 and five times athe number
Ad libitum [116K]
I always use Socratic see if that’ll help
7 0
3 years ago
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× _____ ÷ = <br><br> ALGEBRAALGEBRAALGEBRAALGEBRAALGEBRA
natulia [17]

Answer:

ALGEBRA indeed

Step-by-step explanation:

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3 0
3 years ago
The 2nd, 6th, 8th terms of an A.P. form a G.P. , find the common ratio and the general term of the G.P.​
melisa1 [442]

The terms of an arithmetic progression, can form consecutive terms of a geometric progression.

  • The common ratio is: \mathbf{r = \frac{a + 5d}{a + d}}
  • The general term of the GP is: \mathbf{a_n = (a + d) \times (\frac{a + 5d}{a + d})^{n-1}}

The nth term of an AP is:

\mathbf{T_n = a + (n - 1)d}

So, the <em>2nd, 6th and 8th terms </em>of the AP are:

\mathbf{T_2 = a + d}

\mathbf{T_6 = a + 5d}

\mathbf{T_8 = a + 7d}

The <em>first, second and third terms </em>of the GP would be:

\mathbf{a_1 = a + d}

\mathbf{a_2 = a + 5d}

\mathbf{a_3 = a + 7d}

The common ratio (r) is calculated as:

\mathbf{r = \frac{a_2}{a_1}}

This gives

\mathbf{r = \frac{a + 5d}{a + d}}

The nth term of a GP is calculated using:

\mathbf{a_n = a_1r^{n-1}}

So, we have:

\mathbf{a_n = (a + d) \times (\frac{a + 5d}{a + d})^{n-1}}

Read more about arithmetic and geometric progressions at:

brainly.com/question/3927222

6 0
3 years ago
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