Question

Factorise: 6x^3y^2+9x^2y^3-3x^2y^2​

Answer 1

Answer:

$\boxed{3x^2y^2 (2x+3y-1)}$

Step-by-step explanation:

$6x^3y^2+9x^2y^3-3x^2y^2$

For the three terms, the common factor is $3x^2y^2$, so

$6x^3y^2+9x^2y^3-3x^2y^2 = \boxed{3x^2y^2 (2x+3y-1)}$