3 years ago

Factorise: 6x^3y^2+9x^2y^3-3x^2y^2

Mathematics

1 answer:

Nezavi [6.7K]3 years ago

4 0

Answer:

$\boxed{3x^2y^2 (2x+3y-1)}$

Step-by-step explanation:

$6x^3y^2+9x^2y^3-3x^2y^2$

For the three terms, the common factor is $3x^2y^2$ , so

$6x^3y^2+9x^2y^3-3x^2y^2 = \boxed{3x^2y^2 (2x+3y-1)}$

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Factorise: 6x^3y^2+9x^2y^3-3x^2y^2​

Factorise: 6x^3y^2+9x^2y^3-3x^2y^2