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puteri [66]
3 years ago
13

Factorise: 6x^3y^2+9x^2y^3-3x^2y^2​

Mathematics
1 answer:
Nezavi [6.7K]3 years ago
4 0

Answer:

\boxed{3x^2y^2 (2x+3y-1)}

Step-by-step explanation:

6x^3y^2+9x^2y^3-3x^2y^2

For the three terms, the common factor is 3x^2y^2, so

6x^3y^2+9x^2y^3-3x^2y^2 = \boxed{3x^2y^2 (2x+3y-1)}

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What is the solution to the system y>-2x+2 and y>-2x+5?
ELEN [110]

"y>-2x+2 and y>-2x+5" are illustrated graphically by 2 straight dashed lines with slope -2. The lines are parallel because their slopes (-2) are the same. One line has y intercept 2 and the other has y intercept 5. The latter is above the former. Since both inequality signs are " > " we must shade the area ABOVE each of the 2 lines. The solution set is the area of the graph that has been shaded twice, once for y>-2x+2 and again for y>-2x+5. It's y>-2x+5 that has been shaded twice; this area is immediately above the line y>-2x+5.

3 0
3 years ago
Mr. Jackson has an empty pyramid and an empty prism. The base of the pyramid is congruent to the base of the prism, and their he
IRISSAK [1]
Answer:
Volume of water required to fill the pyramid is rd of the water required to fill the prism completely.
Step-by-step explanation:
Let Mr Jackson has an empty rectangular pyramid and rectangular prism.
Height and base of both are congruent.
So volume of rectangular pyramid

Volume of the rectangular prism = (Area of the base)(height)

[ Since ]


Therefore, amount of water required to fill the pyramid is rd of the water required to fill the prism completely.
8 0
3 years ago
Is the distance jumped a constant or variable
Advocard [28]
It’s a variable because when you justo I can’t stay the same every time it changes
8 0
4 years ago
A tortoise makes a journey in two parts; it can either walk at 4cm/s or crawl at 3cm/s. If the tottoise walks the first part and
Ugo [173]

Answer:

120

240

Step-by-step explanation:

We call the length of first part x

Length of second part = y

In the first scenario, it took the tortoise 110 sec to walk the first part and crawl the second.

So,

We have this equation,

x/4 + y/3 = 110

We take the LCM

(3x + 4y)/12 = 110

When we cross multiply

3x + 4y = 110x12

3x + 4y = 1320 ----- equation 1

For scenario 2

x/3 + y/4 = 100

When we take the LCM

(4x + 3y)/12 = 100

We cross multiply

4x + 3y = 100x12

4x + 3y = 1200 ------ equation 2

We now have two equations and we will solve for x and y using simultaneous linear equation.

3x + 4y = 1320 ----- 1

4x + 3y = 1200 ----- 2

We subtract equation 2 from 1 to get

- x + y = 120

We make y subject

y = x + 120 ----- 3

We put the value of y in equation 3 into equation 1

3x + 4(x + 120) = 1320

3x + 4x + 480 = 1320

7x + 480 = 1320

7x = 1320-480

7x = 840

We divide through by 7

x = 840/7

x = 120

We put value of x in equation 3

y = x + 120

y = 120 + 120

y = 240

120 and 240 are the lengths of the 2 parts of the journey.

Thanks

5 0
3 years ago
PLZ HELP ME I DON'T KNOW
Annette [7]

Answer:

44

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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