Factorise: 6x^3y^2+9x^2y^3-3x^2y^2
1 answer:
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Answer:
0.128
Step-by-step explanation:
We know the probability for any event X is given by,
,
where p is the probability of success and q is the probability of failure.
Here, we are given that p = 0.533.
Since, we have that q = 1 - p
i.e. q = 1 - 0.533
i.e. q = 0.467
It is required to find the probability of 4 wins in the next 5 games i.e. P(X=4) when n = 5.
Substituting the values in the above formula, we get,
i.e.
i.e.
i.e. i.e.
Hence, the probability of 4 wins in the next 5 games is 0.128.