Yes
you let u = sin-1 x and dv = 1 ( so v = x)
and use the rule
INT udv = uv - INT vdu
= x sin^-1 x - INT x sin-1 x
u = sin-1 x so x = sin u
dx/du = cos u , du/dx = 1 / cos u = 1 / sqrt(1 - sin^2) = 1 / sqrt (1-x)^2
so substituting we have
INT sin-1(x) = x sin-1x - INT ( x / sqrt(1- x^2)
= x sun-1 x - ( - sqrt (1 - x^2)
= x sin-1 x + sqrt(1 - x^2) + C
Answer:
y = (3/2)x - (1/2)
Step-by-step explanation:
The general structure of a line in slope-intercept form is:
y = mx + b
In this form, "m" represents the slope and "b" represents the y-intercept. You have been given the value of "m" (3/2). To find the value of "b", you should plug "m" into the equation in addition to the "x" and "y" values from the given point (1,1)
(1,1) ----> x = 1, y = 1
m = 3/2
y = mx + b <----- Slope-intercept form
y = (3/2)x + b <----- Plug (3/2) into "m"
1 = (3/2)(1) + b <----- Plug values into "x" and "y" from point
1 = (3/2) + b <----- Multiply (3/2) and 1
(2/2) = (3/2) + b <----- Change 1 into common denominator
(-1/2) = b <----- Subtract (3/2) from both sides
Because you now have values for both variables, you can construct your final equation.
y = (3/2)x - (1/2)
X would equal 15 because you would divide by 5 to find x
hope i could help you
Answer:
Solution: Part = 2/3 part
Step-by-step explanation:
