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Answer:
Minimum 8 at x=0, Maximum value: 24 at x=4
Step-by-step explanation:
Retrieving data from the original question:
![f(x)=x^{2}+8\:over\:[-1,4]](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E%7B2%7D%2B8%5C%3Aover%5C%3A%5B-1%2C4%5D)
1) Calculating the first derivative

2) Now, let's work to find the critical points
Set this
0, belongs to the interval. Plug it in the original function

3) Making a table x, f(x) then compare
x| f(x)
-1 | f(-1)=9
0 | f(0)=8 Minimum
4 | f(4)=24 Maximum
4) The absolute maximum value is 24 at x=4 and the absolute minimum value is 8 at x=0.
Answer: 706.5
Step-by-step explanation:
A= pi r squared
A= 3.14x15 squared
15 squared = 225
A= 3.14x225
The median is the middle-most number. First we need to put the numbers in order from lowest to highest:
81 84 88 94 94 96
The easiest way to find the median is to cross out the first and last number and then continue until you reach the middle.
So cross out 81 and 96:
84 88 94 94 are left.
Cross out 84 and 94:
88 and 94 are left.
Since we are left with 2 different numbers, we need to find the average of them and that’s our median. (88 + 94)/2 = 91
91 is the median.
Answer:
The vertex of the quadratic function is:

Step-by-step explanation:
Given the function

As the vertex of the form
is defined as:

As the quadratic function of parabola params are

so



Putting
to determine 




Therefore, the vertex of the quadratic function is:
