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Masja [62]
3 years ago
5

Please help! I'm am not that great at graphing like this... Thanks a bunch! :)

Mathematics
1 answer:
Ludmilka [50]3 years ago
3 0

Answer:

Step-by-step explanation:

If it's less than or greater than (<, >), then the circle is hollow.

If it's less than or equal to, or greater than or equal to (≤, ≥), then the circle is solid.

Less than points to the left, greater than points to the right.

Here we have less than (not equal to).  So the circle is hollow, and the arrow points left.  So the correct answer is the first one.

We can check our answer by picking a point and seeing if it's true.  If we pick c=-6, is it true that -6 < -1?  Yes.

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Check out attachment:) I don't understand how do you find out the length ?? pls help with explanation thx
hjlf

Answer:

x=3.89

Step-by-step explanation:

I'll go in depth for you.

Before we figure out what we do, let understand what we know about this triangle.

  • We know that both triangles have a angle that measure 27°.
  • We also know EH=5
  • FG=9
  • ZG=7
  • We need to know how to find EZ

Notice how line EG and HF intersect at Angle Z. We know that if two lines intersect at an angle, it form angles called vertical angles. This means that the two angles that are vertical to each other are congruent.

This means that angle Z in both triangles both measure the same.

Now since both triangles have 2 congruent corresponding angles, we can say that the <em>Triangles</em><em> </em><em>are</em><em> </em><em>Similar</em><em> </em><em>due</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>Angle-Angle</em><em> </em><em>Postulate</em><em>.</em>

<em>"</em><em>If</em><em> </em><em>two</em><em> </em><em> </em><em>corresponding</em><em> </em><em>angles</em><em> </em><em>of</em><em> </em><em>two</em><em> </em><em>triangles</em><em> </em><em>are</em><em> </em><em>congruent</em><em>,</em><em> </em><em>then</em><em> </em><em>the</em><em> </em><em>two</em><em> </em><em>triangles</em><em> </em><em>are</em><em> </em><em>similar</em><em>.</em><em>"</em>

<em>What</em><em> </em><em>is</em><em> </em><em>mean</em><em> </em><em>when</em><em> </em><em>Triangles</em><em> </em><em>are</em><em> </em><em>similar</em><em>?</em><em> </em>

<em>It</em><em> </em><em>means</em><em> </em><em>that</em><em> </em><em>the</em><em> </em><em>similar</em><em> </em><em>triangles</em><em> </em><em>corresponding</em><em> </em><em>angles</em><em> </em><em>are</em><em> </em><em>equal</em><em> </em><em>a</em><em>n</em><em>d</em><em> </em><em>their</em><em> </em><em>sides</em><em> </em><em>are</em><em> </em><em>in</em><em> </em><em>proportion</em><em>.</em>

<em>The</em><em> </em><em>corresponding</em><em> </em><em>sides</em><em> </em><em>are</em><em> </em>

<em>EH</em><em> </em><em>and</em><em> </em><em>GF</em>

<em>EZ</em><em> </em><em>and</em><em> </em><em>ZG</em>

<em>HZ</em><em> </em><em>and</em><em> </em><em>HF</em><em>.</em>

<em>Our</em><em> </em><em>proportion</em><em> </em><em>formula</em><em> </em><em>for</em><em> </em><em>similar</em><em> </em><em>triangle</em><em>s</em><em> </em><em>is</em><em> </em>

<em>Any</em><em> </em><em>two</em><em> </em><em>sides</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>first</em><em> </em><em>triangle</em><em> </em><em>divided</em><em> </em><em>by</em><em> </em><em>each</em><em> </em><em>other</em><em> </em><em>must</em><em> </em><em>equal</em><em> </em><em>the</em><em> </em><em>two</em><em> </em><em>corresponding</em><em> </em><em>sides</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>second</em><em> </em><em>triangles</em><em> </em><em>divided</em><em> </em><em>by</em><em> </em><em>each</em><em> </em><em>other</em><em> </em><em>respectively</em><em>.</em>

<em>We</em><em> </em><em>know</em><em> </em><em>FG</em><em> </em><em>and</em><em> </em><em>ZG</em><em> </em><em>so</em><em> </em><em>let</em><em> </em><em>set</em><em> </em><em>up</em><em> </em><em>our</em><em> </em><em>first</em><em> </em><em>fraction</em>

<em>\frac{fg}{zg}</em>

<em>The</em><em> </em><em>corresponding</em><em> </em><em>sides</em><em> </em><em>of</em><em> </em><em>both</em><em> </em><em>are</em><em> </em>

  • <em>EH</em><em> </em><em>and</em><em> </em><em>EZ</em><em> </em><em>respectively</em><em> </em><em> </em><em>so</em><em> </em><em>our</em><em> </em><em>proportion</em><em> </em><em> </em><em>looks</em><em> </em><em>like</em>
  • <em>\frac{fg}{zg}  =  \frac{eh}{ez}</em>
  • <em>Plug</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>values</em><em> </em><em>for</em><em> </em><em>each</em><em>.</em><em> </em><em>Let</em><em> </em><em>x</em><em> </em><em>represent</em><em> </em><em>the</em><em> </em><em>value</em><em> </em><em>of</em><em> </em><em>EZ</em>
  • <em>\frac{9}{7}  =  \frac{5}{x}</em>
  • <em>Cross</em><em> </em><em>Multiply</em>
  • <em>9x = 35</em>
  • <em>x = 3 \frac{8}{9}  = 3.89</em>
  • <em>So</em><em> </em><em>x</em><em>=</em><em>3</em><em>.</em><em>8</em><em>9</em>
3 0
3 years ago
Jenny,eric and Boris sent a total of 79 text messages during the weekend Jenny sent 6 fewer messages than Erica Boris sent 3 tim
inna [77]
Lets say that J is for Jennys messages, B is for Boris’ and E is for Erics (or Ericas?).

79 = J + B + E

J = E - 6
B = 3E

Since both Jenny’s and Boris’ number of text messages has some kind of relation to Eric’s number of messages, we can say that:

79 = E - 6 (Jenny) + 3E (Boris) + E (Eric), so:

79 = E - 6 + 3E + E /combine like terms
79 = 5E - 6 /add 6 to both sides
79 + 6 = 5E /switch sides + combine like terms
5E = 85 /divide both sides by 5
E = 85/5
E = 17

So, Eric sent 17 messages. Lets get back to those equations we made for Jenny and Boris:

J = E - 6 = 17 - 6 = 11
B = 3E = 3 * 17 = 51

And we can check if it adds up: 51 + 11 + 17 = 79, which is what we were supposed to get.
8 0
3 years ago
In a half-time skills contest Addison received $5 for each free throw she made and $10 for each 3- point shot. She earned a tota
V125BC [204]

Answer:

o.o

Step-by-step explanation:

4 0
3 years ago
Connor earns $23 every 1.5 hours. How many dollars would he earn after working 3 hours and 6 hours
Viefleur [7K]
92 for 6 hrs, and 46 for every 3.
5 0
3 years ago
Read 2 more answers
A can of tuna is shaped like a cylinder.<br> Find its volume to the nearest tenth Use 3.14 for n
Leviafan [203]
The formula for the volume of a cylinder is V=pi*r^2*h 
Since the diameter is 6.8, the radius must be 3.4 (6.8/2)
We can then plug in the given values to solve for the volume
V=3.14*3.4^2*4
V=3.14*11.56*4
V=145.2 so B

Hope this helps
8 0
4 years ago
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