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stiv31 [10]
4 years ago
15

The temperature yesterday was 11 degrees colder than it was today if she represents the temperature today what expression repres

ents the temperature yesterday what was the temperature yesterday today's temperature 68 degrees Fahrenheit
Mathematics
1 answer:
damaskus [11]4 years ago
6 0
68-11=57 (Yesterday's temperature)
That's the expression. ^^ And yesterday's temperature is 57 because, 68 degrees (Today's temperature) minus 11 degrees (how many degrees colder it was yesterday) is equal to 57 degrees (Yesterday's Temperature).

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100 POINTS HELP PLEASE ONE HUNDRED POINTSSS identify each measurement as a diameter, radius, or circumference of the circular ob
ycow [4]

Answer:

1. 15.708

2. The radius would be half of the distance across the drain, or half of the diameter. Half of 3.8cm, or 3.8cm / 2 is 1.9cm.

The circumference is the distance around the drain, or if you trace the entire circle. The formula to find the circumference of a circle is 2 multiplied by pi and the radius of the circle, or C = 2(pi)r. Here, we just found the radius, so the circumference is 2 * pi (which is approximately 3.14) * 1.9cm, or approximately 11.9cm!

Step-by-step explanation:

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3 years ago
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34, 41, 25, 43, ? : mean of 38
Vesna [10]
I'm not sure what the question is but to get the mean you add up all the numbers and divide them by the amount of numbers there are.
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3 years ago
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How to find (c,d,e)<br>Please do a step by step working.Thank you.
Natasha2012 [34]
(a)
The inverse is when you swap the variables and solve for y.
g(t) = 2t - 1 (Note: g(t) represents y)
rewrite as: y = 2t - 1
swap the variables: t = 2y - 1
solve for y: t + 1 = 2y
                   \frac{t + 1}{2} = y
Answer for (a): g^{-1}(t) =  \frac{t + 1}{2}

(b)
Same steps as part (a) above:
h(t) = 4t + 3
rewrite as: y = 4t + 3
swap the variables: t = 4y + 3
solve for y: y =\frac{t - 3}{4}

Answer for (b): h^{-1}(t) = \frac{t - 3}{4}

(c)
g^{-1} ( h^{-1}(t)) =  g^{-1} (\frac{t - 3}{4})
replace all t's in the g^{-1}(t) equation with \frac{t - 3}{4}
 g^{-1} (\frac{t - 3}{4}) = \frac{ \frac{t-3}{4} + 1}{2}
= \frac{ \frac{t-3}{4} +  \frac{4}{4}}{2} = \frac{ \frac{t - 3 + 4}{4}}{2} = \frac{ \frac{t + 1}{4}}{2} =  \frac{t + 1}{8}
Answer for (c): g^{-1} ( h^{-1}(t)) = \frac{t + 1}{8}

 (d)
h(g(t)) = h(2t - 1) = 4(2t - 1) + 3 = 8t - 4 + 3 = 8t - 1
Answer for (d): h(g(t)) = 8t - 1

(e)
h(g(t)) = 8t - 1
   y = 8 t - 1
   t = 8y - 1
  t + 1 = 8y
\frac{t + 1}{8} = y
Answer for (e): inverse of h(g(t)) = \frac{t + 1}{8}
 
























8 0
3 years ago
I need the answers ASAP, please, thank you!
DiKsa [7]
It’s going to be B because
6 0
3 years ago
Let f(x) = 4x + 3 and g(x) = -2x + 5. Find fog 5
Oxana [17]

Answer:

-17

Step-by-step explanation:

first find g(5) = -2(5)+5 = -5

then f(-5) = 4(-5)+3 = -17

6 0
3 years ago
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