In 1906 in San Francisco the magnitude of earthquake on richter scale was 8.3.
In the same year the magnitude of earthquake on richter scale in Japan was 4.9.
Now we have to find how many times more was the San Francisco earthquake that the Japan earthquake.
The amount of energy released in an earthquake is very large, so a logarithmic scale avoids the use of large numbers.
The formula used for these calculations is:
Where M is the magnitude on the richter scale, I is the intensity of the earthquake being measured and I₀ is the intensity of a reference earthquake.
So because the magnitude is a base 10 log, the Richter number is actually the exponent that 10 is raised to in order to calculate the intensity of the earthquake.
So the difference in magnitudes of the earthquakes can be calculated as follows:
M=3.4
Answer: The San Francisco earthquake was 3.4 times more than Japan earthquake.
Answer:
x = 3/4
y = 2.5
Step-by-step explanation:
No there is just one.
Equate the ys
-2/3 x + 3 = 2/3 x + 2 Add 2/3 x to both sides
3 = 2/3 x + 2/3x + 2 Combine
3 = 4/3 x + 2 Subtract 2
3-2 = 4/3 x Multiply by 3
1 * 3 = 4x Divide by 4
3/4 = x
====================
y = 2/3 x + 2
y = 2/3 * 3/4 + 2
y = 6/12 + 2
y = 1/2 + 2
y = 2 1/2
y = 2.5
Answer:
trapezoid
Step-by-step explanation:
There is only one group of shapes that could be a trapezoid
A square, a rectangle, a rhombus, a trapezoid, a kite, and other 4-sided shapes fall under the category of quadrilateral
A rhombus, a parallelogram, and a square are all rhombuses
Answer:
4m^4n^2
Step-by-step explanation:
(16m^7n^3) / (4m^3n)
16/4 = 4
4 (m^7-3)(n^3-1)
4 m4 n^2
688,747,536 ways in which the people can take the seats.
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How many ways are there for everyone to do this so that at the end of the move, each seat is taken by exactly one person?</h3>
There is a 2 by 10 rectangular greed of seats with people. so there are 2 rows of 10 seats.
When the whistle blows, each person needs to change to an orthogonally adjacent seat.
(This means that the person can go to the seat in front, or the seats in the sides).
This means that, unless for the 4 ends that will have only two options, all the other people (the remaining 16) have 3 options to choose where to sit.
Now, if we take the options that each seat has, and we take the product, we will get:
P = (2)^4*(3)^16 = 688,747,536 ways in which the people can take the seats.
If you want to learn more about combinations:
brainly.com/question/11732255
#SPJ!
