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3 years ago

Which visualization tool is more helpful for detecting outliers in data? Select one: a. scatter plot b. histogram c. Boxplot

Mathematics

1 answer:

Tpy6a [65]3 years ago

7 0

Answer:

(A) Scatterplot

Step-by-step explanation:

The most helpful visualization to spot outliers would be a scatterplot.

When collecting data on a scatterplot, you can see how the results are similar and which areas have the most answers and such.

There can be multiply outliers on a scatterplot, and they stand out because while most answers will be clumped together, the outliers will not.

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Find the distance between a point (– 2, 3 – 4) and its image on the plane x+y+z=3 measured across a line (x + 2)/3 = (2y + 3)/4

dimaraw [331]

Answer:

Distance of the point from its image = 8.56 units

Step-by-step explanation:

Given,

Co-ordinates of point is (-2, 3,-4)

Let's say

$x_1\ =\ -2$

$y_1\ =\ 3$

$z_1\ =\ -4$

Distance is measure across the line

$\dfrac{x+2}{3}\ =\ \dfrac{2y+3}{4}\ =\ \dfrac{3z+4}{5}$

So, we can write

$\dfrac{x-x_1+2}{3}\ =\ \dfrac{2(y-y_1)+3}{4}\ =\ \dfrac{3(z-z_1)+4}{5}\ =\ k$

$=>\ \dfrac{x-(-2)+2}{3}\ =\ \dfrac{2(y-3)+3}{4}\ =\ \dfrac{3(z-(-4))+4}{5}\ =\ k$

$=>\ \dfrac{x+4}{3}\ =\ \dfrac{2y-3}{4}\ =\ \dfrac{3z+16}{5}\ =\ k$

$=>\ x\ =\ 3k-4,\ y\ =\ \dfrac{4k+3}{2},\ z\ =\ \dfrac{5k-16}{3}$

Since, the equation of plane is given by

x+y+z=3

The point which intersect the point will satisfy the equation of plane.

So, we can write

$3k-4+\dfrac{4k+3}{2}+\dfrac{5k-16}{3}\ =\ 3$

$=>6(3k-4)+3(4k+3)+2(5k-16)\ =\ 18$

$=>18k-24+12k+9+10k-32\ =\ 18$

$=>\ k\ =\dfrac{13}{8}$

So,

$x\ =\ 3k-4$

$=\ 3\times \dfrac{13}{8}-4$

$=\ \dfrac{7}{4}$

$y\ =\ \dfrac{4k+3}{2}$

$=\ \dfrac{4\times \dfrac{13}{8}+3}{2}$

$=\ \dfrac{19}{4}$

$z\ =\ \dfrac{5k-16}{3}$

$=\ \dfrac{5\times \dfrac{13}{8}-16}{3}$

$=\ \dfrac{-21}{8}$

Now, the distance of point from the plane is given by,

$d\ =\ \sqrt{(x-x_1)^2+(y-y_1)^2+(z-z_1)^2}$

$=\ \sqrt{(-2-\dfrac{7}{4})^2+(3-\dfrac{19}{4})^2+(-4+\dfrac{21}{8})^2}$

$=\ \sqrt{(\dfrac{-15}{4})^2+(\dfrac{-7}{4})^2+(\dfrac{9}{8})^2}$

$=\ \sqrt{\dfrac{225}{16}+\dfrac{49}{16}+\dfrac{81}{64}}$

$=\ \sqrt{\dfrac{1177}{64}}$

$=\ 4.28$

So, the distance of the point from its image can be given by,

D = 2d = 2 x 4.28

= 8.56 unit

So, the distance of a point from it's image is 8.56 units.

4 0

3 years ago

Please help thank you

Shkiper50 [21]

Answer:

x = 0.25

Step-by-step explanation:

When logs are added together, they are actually multiplied and then the logs taken of the product.

That sentence is actually correct, but you are going to have to read it a couple of times. You might understand it if I actually just solve the problem.

ln(2x) + ln(2) = 0 Combine the two subjects to make 1 ln.

ln (2)(2x) = 0 Now take the antilog

ln(4x) = 0

antilog ln(4x) = e^0 e^0 = 1

4x = 1 See your last problem.

x = 1/4

Now the question is "What's the answer?" It might be 1/4 but I doubt it. A better choice would be x = 1/4 or x = 0.25

I'd try the last one first.

6 0

2 years ago

PLS HELP ME 15 points in total

lilavasa [31]

Answer:

Its 53 because 1=1 and 2=2

Step-by-step explanation:

8 0

1 year ago

Helen sold 50 cups of lemon aid and made $36. What was the cost per cup

Ivan

Answer:

$1.39

Step-by-step explanation:

50/36=1.39

6 0

3 years ago

Please help asap 30 pts

Flura [38]

D. Using a graphing calculator, compare the two graphs. The function y= square root x+3 is shifted 3 units to the left of the function y=square root x.

3 0

3 years ago