Answer:
it may be registered or register, or registering. i am not entirely sure.
Step-by-step explanation:
Answer:
f'(x) = -f(x) = 9xy² - 6x²y + 5x³
Step-by-step explanation:
f(x) = –9xy² + 6x²y – 5x³
additive inverse: f'(x) = -f(x) = 9xy² - 6x²y + 5x³
f(x) + f'(x) = f(x) -f(x) = (–9xy² + 6x²y – 5x³) + (9xy² - 6x²y + 5x³) = 0
Answer: 23498.935
Step-by-step explanation:
this helped me in middle school so please remember this equation
A=P(1+R/N)NT
A=AMOUNT
P=PRINCIPAL
R=INTEREST RATE
N=NUMBERS OF TIMES THE INTEREST IS COMPOUNDED
NT=TIME(YEARS
So now we have this... right...
A=P(1+R/N)NT
you have to fill it in and you will get
a=22,150(1+3/1)^2
put that in your handy dandy calculator and you will get your answer
Answer:
![\vec s = \left(\frac{1}{2},\frac{\sqrt{3}}{2} \right)](https://tex.z-dn.net/?f=%5Cvec%20s%20%3D%20%5Cleft%28%5Cfrac%7B1%7D%7B2%7D%2C%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B2%7D%20%20%5Cright%29)
Step-by-step explanation:
The coordinate has the following polar form:
![\vec r = (1, 0^{\circ})](https://tex.z-dn.net/?f=%5Cvec%20r%20%3D%20%281%2C%200%5E%7B%5Ccirc%7D%29)
The image of the coordinate rotated counterclockwise 60° is:
![\vec s = (1, 60^{\circ})](https://tex.z-dn.net/?f=%5Cvec%20s%20%3D%20%281%2C%2060%5E%7B%5Ccirc%7D%29)
Its equivalent form in rectangular coordinates is:
![\vec s = (1\cdot \cos 60^{\circ}, 1 \cdot \sin 60^{\circ})](https://tex.z-dn.net/?f=%5Cvec%20s%20%3D%20%281%5Ccdot%20%5Ccos%2060%5E%7B%5Ccirc%7D%2C%201%20%5Ccdot%20%5Csin%2060%5E%7B%5Ccirc%7D%29)
![\vec s = \left(\frac{1}{2},\frac{\sqrt{3}}{2} \right)](https://tex.z-dn.net/?f=%5Cvec%20s%20%3D%20%5Cleft%28%5Cfrac%7B1%7D%7B2%7D%2C%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B2%7D%20%20%5Cright%29)
Choice B.
how you can determine is to look at the x coordinates. If you see two x coordinates, and they have different corresponding y values, then the set is not a function.