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mario62 [17]
3 years ago
6

I really need a 100 I'm felling in all my classes, please

Mathematics
2 answers:
german3 years ago
8 0

Answer:

There is no picture, or diagram with the question, but 1/6 = 2/12

pashok25 [27]3 years ago
7 0

Answer:

2/12

Step-by-step explanation:

1/6 * 2 = 2/12

Multiply both numerator and denomanotor

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Guys I need help in both please​
IRINA_888 [86]

Answer:

Graph 1 is not proportional

Graph 2 is proportional - y is 2 times x

Step-by-step explanation:

In graph 1, there is no x-y correlation

In graph 2, there is, when x=1, y=6

when x=2, y=12. Therefore, when x=3 y would equal 18.

4 0
3 years ago
Find a and b if the point p(6,0) and Q(3,2) lie on the graph of ax+ by=12
tiny-mole [99]

to get the equation of any straight line we only need two points off of it, hmmm let's use P and Q here and then let's set the equation in standard form, that is

standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

(\stackrel{x_1}{6}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{0}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{6}}}\implies \cfrac{2}{-3}\implies -\cfrac{2}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{2}{3}}(x-\stackrel{x_1}{6})

\stackrel{\textit{multiplying both sides by }\stackrel{LCD}{3}}{3(y-0)~~ = ~~3\left( -\cfrac{2}{3}(x-6) \right)}\implies 3y=-2(x-6) \\\\\\ 3y=-2x+12 \implies \stackrel{a}{2} x+\stackrel{b}{3} y=12

5 0
2 years ago
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