Answer:
![\left[\begin{array}{cccc}1&3&4&5\&3&1&5&6\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%263%264%265%5C%263%261%265%266%5Cend%7Barray%7D%5Cright%5D)
The only ones are on the "diagonal", where i = j. Else the position is simply the sum.
I can't see a square or a D given with your question.
But to find the perimeter you just have to add the surface of every side of the square.
Try 6578 :) I think that may be right,
Answer:
see explanation
Step-by-step explanation:
The sum of the 3 angles in the triangle = 180°
Sum the 3 angles and equate to 180
31 + x + 4 + 3x + 9 = 180, that is
4x + 44 = 180 ( subtract 44 from both sides )
4x = 136 ( divide both sides by 4 )
x = 34
Thus
∠ S = x + 4 = 34 + 4 = 38°
∠ T = 3x + 9 = 3(34) + 9 = 102 + 9 = 111°
Answer:
C
24Step-by-step explanation:
Trust me on this one.
