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olga_2 [115]
3 years ago
6

Adding which of the following ordered pairs to the set [(0, 1), (2, 4), (3,5)) would make it not a function?

Mathematics
1 answer:
Kitty [74]3 years ago
3 0

Answer:

(0,7)

Step-by-step explanation:

For a set of ordered pairs to be a function, there needs to be "ONE" value of y for each unique x value.

Thus, we see that the 3 ordered pairs given have x values of 0, 2, and 3.

Now, we look in the answer choices and find which ones are 0, 2, or 3 in x-coordinate.

That would be only (0,7). Now the original set has x = 0 corresponding to y = 1

Is that true for (0,7)?? NO!

x = 0 will now correspond to "TWO" values of y.

THis will make this NOT A FUNCTION.

So, (0,7) is correct.

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Answer:

Step-by-step explanation:

√3y/√y

= √(3y/y)

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5 0
3 years ago
A car travels 350 miles on 20 gallons of gasoline how many gallons will be used to travel 875 miles under the same conditions
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6 0
3 years ago
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Some airlines have restrictions on the size of items of luggage that passengers are allowed to take with them. Suppose that one
olga_2 [115]

Answer:

Length = Width = Height = 64 ; Luggage Box is a CUBE

Step-by-step explanation:

Given : Length (L) + Width (W) + Height (H) ≤ 192 ; & Length = Width

Volume ( V )of luggage [Cuboid] = L.W.H

Since L = W :

V = L.L.H  → V = L^2H  

L + L + H = 192 →  2L + H = 192 → H = 192 - 2L

Putting value of 'H' in 'V'

V = L^2 (192 - 2L) → V = 192L^2 - 2L^3

Maximising volume function , differentiating it w.r.t 'L'

dV / dL = 2(192 L) - 3 (2L^2)  → = 384L - 6L^2

dV / dL = 384L - 6L^2  = 0

384L = 6L^2 → 384 = 6L

L = 384 / 6 → L = 64  ; W also = 64

Putting value of L in 1st given sum equation : 2L + H = 192

2 (64) + H = 192

128 + H = 192 → H = 192 - 128 → H = 64

Since L = W = H = 64 ; Luggage bag is a Cube

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1. Find the value for the expression when h=13: 9 + h - 3
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