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olga_2 [115]
3 years ago
6

Adding which of the following ordered pairs to the set [(0, 1), (2, 4), (3,5)) would make it not a function?

Mathematics
1 answer:
Kitty [74]3 years ago
3 0

Answer:

(0,7)

Step-by-step explanation:

For a set of ordered pairs to be a function, there needs to be "ONE" value of y for each unique x value.

Thus, we see that the 3 ordered pairs given have x values of 0, 2, and 3.

Now, we look in the answer choices and find which ones are 0, 2, or 3 in x-coordinate.

That would be only (0,7). Now the original set has x = 0 corresponding to y = 1

Is that true for (0,7)?? NO!

x = 0 will now correspond to "TWO" values of y.

THis will make this NOT A FUNCTION.

So, (0,7) is correct.

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55 and 45 find the the percent decrease round to the nearest whole number
Helen [10]

Answer:

18.18%

Step-by-step explanation:

55-45=10

10/55=0.18

5 0
3 years ago
Jeff uses 3 fifth-size strips to mode 3/5. He wants to use tenth-size strips to model an equivalent fraction. How many tenth-siz
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Wouldn't it just be 6 tenth sized for 6/10
4 0
4 years ago
I don’t understand this
Oxana [17]

You have to multiply whats outside the parenthesis with everything that is inside, so

x^{-3}y^0.(x^2-3x^5y^4)

x^{-3}y^0.x^2-x^{-3}y^0.3x^5y^4

Multiplication of same bases we sum the exponents

x^{-3+2}y^0-3x^{-3+5}y^{0+4}

x^{-1}.1-3x^2y^4

x^{-1}-3x^2y^4

Alternative B.

7 0
3 years ago
Suppose the following number of defects has been found in successive samples of size 100: 6, 7, 3, 9, 6, 9, 4, 14, 3, 5, 6, 9, 6
Brut [27]

Answer:

Given the data in the question;

Samples of size 100: 6, 7, 3, 9, 6, 9, 4, 14, 3, 5, 6, 9, 6, 10, 9, 2, 8, 4, 8, 10, 10, 8, 7, 7, 7, 6, 14, 18, 13, 6.

a)

For a p chart ( control chart for fraction nonconforming), the center line and upper and lower control limits are;

UCL = p" + 3√[ (p"(1-P")) / n ]

CL = p"

LCL = p" - 3√[ (p"(1-P")) / n ]

here, p" is the average fraction defective

Now, with the 30 samples of size 100

p" =  [∑(6, 7, 3, 9, 6, 9, 4, 14, 3, 5, 6, 9, 6, 10, 9, 2, 8, 4, 8, 10, 10, 8, 7, 7, 7, 6, 14, 18, 13, 6.)] / [ 30 × 100 ]

p" = 234 / 3000

p" = 0.078

so the trial control limits for the fraction-defective control chart are;

UCL = p" + 3√[ (p"(1-P")) / n ]

UCL = 0.078 + 3√[ (0.078(1-0.078)) / 100 ]

UCL = 0.078 + ( 3 × 0.026817 )

UCL = 0.078 + 0.080451

UCL = 0.1585

LCL = p" - 3√[ (p"(1-P")) / n ]

LCL = 0.078 - 3√[ (0.078(1-0.078)) / 100 ]

LCL = 0.078 - ( 3 × 0.026817 )

LCL = 0.078 - 0.080451

LCL =  0 ( SET TO ZERO )

Diagram of the Chart uploaded below

b)

from the p chart for a) below, sample 28 violated the first western electric rule,

summary report from Minitab;

TEST 1. One point more than 3.00 standard deviations from the center line.

Test failed at points: 28

Hence, we conclude that the process is out of statistical control

Lets Assume that assignable causes can be found to eliminate out of control points.

Since 28 is out of control, we should eliminate this sample and recalculate the trial control limits for the P chart.

so

p" = 0.0745

UCL = p" + 3√[ (p"(1-P")) / n ]

UCL = 0.0745 + 3√[ (0.0745(1-0.0745)) / 100 ]

UCL = 0.0745 + ( 3 × 0.026258 )

UCL = 0.0745 + 0.078774

UCL = 0.1532

LCL  = p" - 3√[ (p"(1-P")) / n ]

LCL = 0.0745 - 3√[ (0.0745(1-0.0745)) / 100 ]

LCL = 0.0745 - ( 3 × 0.026258 )

LCL = 0.0745 - 0.078774

UCL = 0  ( SET TO ZERO )

The second p chart diagram is upload below;

NOTE; the red circle symbol on 28 denotes that the point is not used in computing the control limits

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3 years ago
What times 85 dives you 2790
musickatia [10]

Answer:

34.875

Step-by-step explanation:

4 0
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