Answer:
Step-by-step explanation:
hello,
I understand that there are only 4 cards and then the player draw a card out of the 4 cards, replace it so the second draw is still out of the 4 cards
<u>How many ways can you draw two cards?</u>
as the first card is replaced, this is 4*4=16
so there is 16 possibles ways
hearts hearts
hearts clubs
hearts diamonds
hearts spades
clubs hearts
clubs clubs
clubs diamonds
clubs spades
diamonds hearts
diamonds clubs
diamonds diamonds
diamonds spades
spades hearts
spades clubs
spades diamonds
spades spades
<u>out of these 16 ways, how many have same colour for both cards?</u>
I assume that there are only two colours Red and Black, so we can have
only 8 ways so the first probability is 8/16 = 1/2
<u>out of these 16 ways, how many are red ace first and black ace?</u>
There are 4 ways so the probability is 4/16 = 1/4
hope this helps
Answer: I'm assuming you just need to graph each ordered pair without doing anything else to them. The first number in the ordered pair is called the x-intercept, the second number is the y-intercept. To graph an ordered pair you need to count the x-intercept number and go to that number on the x-axis (horizontal), do the same for the y-intercept on the y-axis (vertical) and make a point/dot. Repeat this for the other two ordered pairs.
Answer:
19.0681
Step-by-step explanation:
Given in the question that,
angle from ted to the dog = 60° with the ground
height of ted from the ground = 16ft
To find,
distance between dog and the door of ted's building
Considering the scenario make a right angle triangle:
<h3>By using pythagorus theorem:</h3>
Tan 40 = opposite / adjacent
Tan 40 = height / distance between dog and the door
Tan 40 = 16ft / x
x = 16 / tan40
x = 19.068057
x ≈ 19.0681 (nearest to thousand)
So, the dog need to walk 19.0681ft to reach the open door directly below Ted.
Answer:
a). 
m
b). 
m³
c). 
N²
Step-by-step explanation:
In this question we have to convert each option into SI units.
a). 
mm
= 
m
= m
b). (348 mm)³
= 
m³
= 
m³
= m³
c). 
N²
= 
N²
= 
= N²
