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Gala2k [10]
3 years ago
12

Solve the following system of equations using the

Mathematics
1 answer:
ikadub [295]3 years ago
5 0

Answer:

x = 3, y = - 1, z = 1

Step-by-step explanation:

listing the coefficients

1   - 2   1   6 ← R1

3    1    - 1  7 ← R2

4   - 1     2   15 ← R3

We require the first entry in R2 to be 0 while retaining R1 and the first 2 entries of R3 to be 0, thus

R2 - 3R1 and R3 - 4R1

1   - 2   1    6 ← R1

0    7   - 4  - 11 ← R2  

0    7    - 2  - 9 ← R3

Now R3 - R2

1    - 2    1     6 ← R1

0     7   - 4   - 11 ← R2

0    0      2    2 ← R3

From R3

2z = 2 ⇒ z = 1

Substitute z = 1 into R2

7y - 4(1) = - 11

7y - 4 = - 11 ( add 4 to both sides )

7y = - 7 ⇒ y = - 1

Substitute y = - 1, x = 1 into R1

x - 2(- 1) + 1 = 6

x + 2 + 1 = 6

x + 3 = 6 ( subtract 3 from both sides )

x = 3

Solution is (3, - 1, 1 )

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3 years ago
Simplify 3√20/√5<br><br> a)25/4<br> b)6<br> c)√5/5<br> d2√3/15
Blizzard [7]
<span>3√20/√5
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3 years ago
Which equation has the solutions x = startfraction 5 plus-or-minus 2 startroot 7 endroot over 3 endfraction?
Shtirlitz [24]

The equation that has the solution x = \frac{5 \pm \sqrt{7}}{3} is 3x^2 - 10x + 6 = 0

<h3>How to determine the equation?</h3>

The solution is given as:

x = \frac{5 \pm \sqrt{7}}{3}

The solution to a quadratic equation is

x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

By comparing both equations, we have:

-b = 5

b^2 - 4ac = 7

2a = 3

Solve for b in -b = 5

b = -5

Solve for a in 2a = 3

a = 1.5

Substitute values for a and b in b^2 - 4ac = 7

(-5)^2 - 4 * 1.5c = 7

Evaluate

25 - 6c = 7

Subtract 25 from both sides

-6c = -18

Divide by - 6

c = 3

So, we have:

a = 1.5

b =  -5

c = 3

A quadratic equation is represented as:

ax^2 + bx + c = 0

So, we have:

1.5x^2 - 5x +3 = 0

Multiply through by 2

3x^2 - 10x + 6 = 0

Hence, the equation that has the solution x = \frac{5 \pm \sqrt{7}}{3} is 3x^2 - 10x + 6 = 0

Read more about quadratic equation at:

brainly.com/question/1214333

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2 years ago
What is the probability of rolling a 4 or higher on a six sided number cube
Trava [24]
P(rolling a 4)=1/6

Explanation:
The probability of rolling a 4 or higher on a 6-sided number cube is 1/6

Answer: 1/6
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Answer:

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Step-by-step explanation:

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