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mel-nik [20]
3 years ago
13

Tangent line of f(x) = sec x @ (pi/3, 2)

Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
3 0
The derivitive of sec(x) is sec(x)tan(x)

find the slope at pi/3

sec(pi/3)=2
tan(pi/3)=√3

sec(x)tan(x) at x=pi/3 is 2√3

for slope=m and a point is (x1,y1)
the equation is
y-y1=m(x-x1)
slope=2√3
point=(pi/3,2)

equation is
y-2=2√3(x-pi/3)
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The spending limit on John's credit card is given by the function f(t) = 15,000 + 1.57, where x is his monthly income. 1-13) $60
coldgirl [10]
1.
"The spending limit on John’s credit card is given by the function f(x)=15,000+1.5x"

means that if the monthly income of John is $ 5,000 ,he can spend at most

f(5,000)=15,000+1.5*5,000=15,000+ 7,500=22, 500 (dollars)

Or for example

if Johns monthly income is $8,000, then he can spend at most

f(8,000)=15,000+1.5*8,000=15,000+ 12,000=27,000 (dollars)


2.
Now, assume that the maximum amount that John can spend is y.

Then, y=15,000+1.5x

we can express x, the monthly income, in terms of y by isolating x:

y=15,000+1.5x

1.5x = y-15,000
X=y-15,000/1.5

thus, in functional notation, x, the monthly income, is a function , say g, of variable y, the max amount:
X=g(y) y-15000/1.5
since we generally use the letter x for the variable of a function, we write g again as:

G (x) x-15000/1.5
tells us that if the maximum amount that John can spend is 50,000 $, then his monthly income is 23,333 $.

3.

If John's limit is $60,000, his monthly income is
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dollars.


Answer: $ 30,000

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3 years ago
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2 years ago
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Find the slope of the line passing through the pairs of points and describe the line as rising, falling, horizontal or vertical.
Anna [14]

Answer:

a.\ m=2,\ \text{the line is rising}\\\\b.\ m=-\dfrac{5}{4},\ \text{the line is falling}\\\\c.\ m=0,\ \text{the line is horizontal}\\\\d.\ m\ is\ unde fined,\ \text{the line is vertical}

Step-by-step explanation:

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

If

m > 0, then a line is rising

m < 0, then a line is falling

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m is undefined, then a line is vertical

<h2>a.</h2>

(2, 1) and (4, 5)

m=\dfrac{5-1}{4-2}=\dfrac{4}{2}=2>0\to\text{rising}

<h2>b.</h2>

(-1, 0) and (3, -5)

m=\dfrac{-5-0}{3-(-1)}=\dfrac{-5}{4}=-\dfrac{5}{4}

<h2>c.</h2>

(2, 1) and (-3, 1)

m=\dfrac{1-1}{-3-2}=\dfrac{0}{-5}=0\to\text{horizontal}

<h2>d.</h2>

(-1, 2) and (-1, -5)

m=\dfrac{-5-2}{-1-(-1))}=\dfrac{-7}{0}\ \text{UNDEFINED}\to\text{vertical}

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3 years ago
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