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mel-nik [20]
3 years ago
13

Tangent line of f(x) = sec x @ (pi/3, 2)

Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
3 0
The derivitive of sec(x) is sec(x)tan(x)

find the slope at pi/3

sec(pi/3)=2
tan(pi/3)=√3

sec(x)tan(x) at x=pi/3 is 2√3

for slope=m and a point is (x1,y1)
the equation is
y-y1=m(x-x1)
slope=2√3
point=(pi/3,2)

equation is
y-2=2√3(x-pi/3)
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The produce manager at a market orders 10 lb of​ tomatoes, 20 lb of​ zucchini, and 40 lb of onions from a local farmer one week.
rewona [7]

Answer:

(A) A=\left[\begin{array}{ccc}10&20&40\end{array}\right]

(B) B=\left[\begin{array}{ccc}11&22&44\end{array}\right]

(C) A+B=\left[\begin{array}{ccc}21&42&84\end{array}\right]

Step-by-step explanation:

The manager ordered 10 lb of​ tomatoes, 20 lb of​ zucchini, and 40 lb of onions from a local farmer one week.

(A)

Matrix <em>A</em> represents the amount of each item ordered. ​It is 1 × 3 matrix.

Then matrix <em>A</em> is:

A=\left[\begin{array}{ccc}10&20&40\end{array}\right]

(B)

Next week the manager increases the order of all the products by 10%.

Then the amount of new orders are:

Tomatoes =10\times [1+\frac{10}{100}]=10\times1.10=11

Zucchini =20\times [1+\frac{10}{100}]=20\times1.10=22

Onions =40\times [1+\frac{10}{100}]=40\times1.10=44

Th matrix <em>B</em> represents the amount of each order for the next week. Then matrix <em>B</em> is:

B=\left[\begin{array}{ccc}11&22&44\end{array}\right]

(C)

Add the two matrix <em>A</em> and <em>B</em> as follows:

A+B=\left[\begin{array}{ccc}10&20&40\end{array}\right]+\left[\begin{array}{ccc}11&22&44\end{array}\right]\\=\left[\begin{array}{ccc}(10+11)&(20+22)&(40+44)\end{array}\right]\\=\left[\begin{array}{ccc}21&42&84\end{array}\right]

The entries of the matrix (<em>A</em> + <em>B</em>) represent the amount of tomatoes, zucchini and onions ordered for two weeks.

5 0
3 years ago
Can someone help me on this?
Anna [14]
The answer would be B
5 0
3 years ago
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