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Natalija [7]
3 years ago
10

Can someone help me please.

Mathematics
2 answers:
bazaltina [42]3 years ago
7 0
The answer is B. And I am not that sure about my answer, but it has to be the correct answer for what you put. THANK YOU!!!!
ElenaW [278]3 years ago
4 0
Yea the answer is B
The other person is correct lol
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Find the 14th term of the geometric sequence 2, 6, 18,
butalik [34]

The geometric sequence is starting with 2 and multiplying by 3 every time. We can get the rule of this sequence by...

If 2 is a_0, 6 is a_1, 18 is a_2, etc.

a_n=2*3^n

For the 14th term, which is a_13, the value is 2*3^13.

Using a calculator because I'm too lazy to calculate 3^13 sorry, we can get.

3188646

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3 years ago
Please answer this please
cluponka [151]

Step-by-step explanation:

<h3>1. x² + 4 = (x+2)² </h3>

<h3> : x² + 4 = x² + 4 (Yes)</h3>

<h3>2. (2x+6)²= 4(x+3)²</h3>

<h3> : 4x²+36 = 4x² + 36 ( Yes)</h3>

<h3>3. (x-3)(x-3)= (x-9)² (NO)</h3>

<h3>beacause , True statement is</h3><h3> (x+3)(x-3)= (x-9)²</h3>

<h3>4. x²-10x+25 = (x-5)(x+5) (No)</h3>

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3 years ago
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3 years ago
Factor. 49x^2−36y^2 <br> Enter your answer in the boxes.
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The three modes are 5, 12, and 150 since they occur the most times and they tie one another in being the most frequent (each occurring 3 times).

Only the 7 and 8 occur once each, and aren't modes. Everything else is a mode. It's possible to have more than one mode and often we represent this as a set. So we'd say the mode is {5, 12, 150} where the order doesn't matter.

4 0
3 years ago
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