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sergij07 [2.7K]
3 years ago
10

What is the geometric mean of 3 and 15

Mathematics
1 answer:
Helen [10]3 years ago
4 0
Trick question. There is not one. Due to the fact that 3 is a factor of 15 and if you factor it you will get five which is a third of 15. 
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3. If triangle ABC has the following measurements, find the measure of angle A.
klio [65]

9514 1404 393

Answer:

  (a)  42.3°

Step-by-step explanation:

Side 'a' is the shortest of three unequal sides, so angle A will be the smallest angle in the triangle. Its measure can be found from the Law of Cosines.

  a² = b² +c² -2bc·cos(A)

  cos(A) = (b² +c² -a²)/(2bc) = (21² +25² -17²)/(2·21·25) = 777/1050

  A = arccos(777/1050) ≈ 42.3°

The measure of angle A is about 42.3°.

_____

<u><em>Additional comment</em></u>

The smallest angle in a triangle can never be greater than 60°. This lets you eliminate choices that exceed that value.

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3 years ago
Anna and Maya are competing in a dance tournament where dance moves are worth a certain number of points if a dance move it's do
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Anna's current number of points = 225 points.

She danced correctly and earned = 75 points.

And when she danced incorrectly she loses = 30 points.

Note: For dancing correctly earned points will be added and for dancing incorrectly loses points will be subtracted from the total points has in starting.

So, we can setup an expression as

Current points + earned points - loses points

Plugging values, we get

225 +75 -30   Required expression.

Adding 225 and 75, we get 300.

Therefore, 225 +75 -30 = 300-30.

Subtracting 30 from 300, we get

300-30=270.

Therefore, Anna's final score is 270 points.

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Varvara68 [4.7K]
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\bf \qquad \textit{Compound Interest Earned Amount}&#10;\\\\&#10;A=P\left(1+\frac{r}{n}\right)^{nt}&#10;\quad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\to &\$4432.37\\&#10;P=\textit{original amount deposited}\to &\$3000\\&#10;r=rate\to r\%\to \frac{r}{100}\\&#10;n=&#10;\begin{array}{llll}&#10;\textit{times it compounds per year}\\&#10;\textit{annually, thus once}&#10;\end{array}\to &1\\&#10;t=years\to &8&#10;\end{cases}

\bf 4432.37=3000\left(1+\frac{r}{1}\right)^{1\cdot 8}\implies \cfrac{4432.37}{3000}=(1+r)^8&#10;\\\\\\&#10;\sqrt[8]{\cfrac{4432.37}{3000}}=1+r\implies \sqrt[8]{\cfrac{4432.37}{3000}}-1=r&#10;\\\\\\&#10;0.0500001086\approx r\qquad\qquad\cfrac{r\%}{100}\approx 0.0500001086&#10;\\\\\\&#10;r\%\approx 100\cdot 0.0500001086\implies r=\stackrel{\%}{5}
6 0
3 years ago
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