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3 years ago

What is the geometric mean of 3 and 15

1 answer:

4 0

Trick question. There is not one. Due to the fact that 3 is a factor of 15 and if you factor it you will get five which is a third of 15.

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Can anyone help me with this

Nataliya [291]

To find surface area, we can use the equation:

SA=2lw+2wh+2lh, where:
l=10 in
w=3 in
h=7 in

SA=(2)(10)(3)+(2)(3)(7)+(2)(10)(7)
SA=60+42+140
SA=242 in²

5 0

3 years ago

Describe the diagram below using correct geometric names

bagirrra123 [75]

Angles PQT and RQS are vertical angles and angles PQR and TQS are vertical angles.

angle PQS and TQR are straight angles

angles TQP and PQR form a linear pair. they are also adjacent by default. the other angles have these same features.

that should bout do it. hope it helped!

7 0

3 years ago

What's the answer? Can someone help me?

Readme [11.4K]

Answer:

Area = 12

i attached the formula to ger the area with the perimeter

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3 years ago

amortization for house costs 35,000.00 at 6.5% interest for 10 years and payments of 400.00 were paid for 36 months what is the

UNO [17]

Answer:

$26,640.22

Step-by-step explanation:

8 0

2 years ago

Given that f(–2.4) = -1 and f(-1.9) = -8, approximate f'(-2.4). f'(-2.4)

lora16 [44]

Answer:

f'(-2.4) ≈ -14

General Formulas and Concepts:
Algebra I

Coordinate Planes

Coordinates (x, y)

Slope Formula: $\displaystyle m = \frac{y_2 - y_1}{x_2 - x_1}$

Functions

Function Notation

Calculus

Differentiation

Derivatives
Derivative Notation

Step-by-step explanation:

*Note:

The definition of a derivative is the slope of the tangent line.

Step 1: Define

Identify.

f(-2.4) = -1

f(-1.9) = -8

Step 2: Differentiate

Simply plug in the 2 coordinates into the slope formula to find slope m.

[Derivative] Set up [Slope Formula]: $\displaystyle f'(-2.4) \approx \frac{f(x_2) - f(x_1)}{x_2 - x_1}$
Substitute in coordinates: $\displaystyle f'(-2.4) \approx \frac{-8 - -1}{-1.9 - -2.4}$
Evaluate: $\displaystyle f'(-2.4) \approx -14$

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Learn more about derivatives: brainly.com/question/17830594

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Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

6 0

2 years ago