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3 years ago

Which problem could be solved with the expression 4*(4+2)

1 answer:

3 0

The answer is A.

He ran for six (6) miles every day. 4 in the morning and 2 at night = 6 per day.

He did this for four (4) days. The way to figure this would be to go 6 * 4. This equals 24 miles.

Go back a few steps (punny!).

So days multiplied by how many miles he ran a day which is calculated by miles in morning added to miles at night.

days*(miles per morning + miles per night)

days=4
miles per morning=4
miles per night = 2

4 * (4+2)

Calculating this out....

4 * (4+2)

(4+2 = 6)

4 * 6 = 24.

So A is the answer.

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3 years ago

A team of 3 QA testers and l QA team lead is working on a project. The team finishes

valina [46]

The team-lead gets $2000 if the team of 3 QA testers and l QA team lead is working on a project. The team finishes the job and is paid.

<h3>What is average?</h3>

It is defined as the single number that represents the mean value for the given set of data or the closed value for each entry given in the set of data.

Let's suppose the team lead salary is x and the team-lead receives, $600 more than the average salary of the entire team then,

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6 0

1 year ago

En una fiesta hay 40 asistentes de los cuales el número de varones que no bailan es el doble que el número de las mujeres que no

Arte-miy333 [17]

Answer:

50%

Step-by-step explanation:

Para resolver este problema vamos a definir 4 variables:

V= número de varones bailando.

M= número de mujeres bailando.

V' = número de varones que no están bailando.

M' = número de mujeres que no están bailando.

Sabemos que hay 40 personas en la fiesta, por lo que podemos construir la siguiente ecuación:

V+M+V'+M'=40

Vamos a suponer que cada mujer que está bailando, está bailando varón respectivamente. (El problema no da más información, entonces podemos suponer esto.)

Entonces si hay 5 mujeres bailando, entonces también hay 5 hombres bailando, por lo que nuestra ecuación se reescribe de la siguiente manera:

5+5+V'+M'=40

y simplificamos:

10+V'+M'=40

V'+M'=40-10

V'+M'=30

Ahora bien, el problem nos dice que el número de varones que no bailan es el doble del número de mujeres que no bailan en un determinado momento. Entonces con esta información podemos construir la siguiente ecuación:

V'=2M'

Y podemos despejar el número de mujeres que no bailan, lo que nos da:

$M'=\frac{V'}{2}$

Entonces podemos sustituir esto dentro de nuestra ecuación para obtener:

$\frac{V'}{2}+V'=30$

y podemos entonces despejar V'

$\frac{3V'}{2}=30$

$V'=\frac{2(30)}{3}$

V'=20

Entonces hay 20 varones que no están bailando, por lo que la probabilidad de que el varón que se escoge al azar no esté bailando está dada por la siguiente fórmula:

$P=\frac{V'}{total}$

$P=\frac{20}{40}=\frac{1}{2}$

P=50%

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2 years ago