Please help me with this!<br> Solve:<br> 4+(−8+s)=204+(−8+s)=20 s=8s=8 s=16s=16 s=24s=24 s=−4

PLS HELP !!! I NEED HELP PLS ILL APPRECIATE IT SM!

bazaltina [42]

Answer:

$\frac{3}{4}$

Step-by-step explanation:

ok so first you want to find a common factor. For instance, 3. So divide the numerator and denominator by 3. This will give you the fraction of $\frac{3}{4}$ .

5 0

3 years ago

Read 2 more answers

What is the square root of 85

dimulka [17.4K]

Answer:

Step-by-step explanation:

√85 = 9.219544457292887310002274281762...

8 0

2 years ago

Read 2 more answers

In the diagram, parallel lines P and Q are cut by transversal R.

Paraphin [41]

Answer:

x=125

Step-by-step explanation:

7 0

3 years ago

I need help with these ASAP thanks

Nataly_w [17]

Answer:

a. $y=\frac{2x}{x-5}$

b. $y=\frac{2-4x}{x-3}$

Step-by-step explanation:

change switch x and y and then solve for y.

a. $x=\frac{5y}{y-2}$

$x(y-2)=5y$

$xy-2x=5y$

$xy-5y=2x$

$y(x-5)=2x$

$y=\frac{2x}{x-5}$

same for b.

b. $x=\frac{3y+2}{y+4}$

$x(y+4)=3y+2$

$xy+4x=3y+2$

$xy-3y=2-4x$

$y(x-3)=2-4x$

$y=\frac{2-4x}{x-3}$

4 0

3 years ago

the height h(t) of a trianle is increasing at 2.5 cm/min, while it's area A(t) is also increasing at 4.7 cm2/min. at what rate i

nekit [7.7K]

Answer:

The base of the triangle decreases at a rate of 2.262 centimeters per minute.

Step-by-step explanation:

From Geometry we understand that area of triangle is determined by the following expression:

$A = \frac{1}{2}\cdot b\cdot h$ (Eq. 1)

Where:

$A$ - Area of the triangle, measured in square centimeters.

$b$ - Base of the triangle, measured in centimeters.

$h$ - Height of the triangle, measured in centimeters.

By Differential Calculus we deduce an expression for the rate of change of the area in time:

$\frac{dA}{dt} = \frac{1}{2}\cdot \frac{db}{dt}\cdot h + \frac{1}{2}\cdot b \cdot \frac{dh}{dt}$ (Eq. 2)

Where:

$\frac{dA}{dt}$ - Rate of change of area in time, measured in square centimeters per minute.

$\frac{db}{dt}$ - Rate of change of base in time, measured in centimeters per minute.

$\frac{dh}{dt}$ - Rate of change of height in time, measured in centimeters per minute.

Now we clear the rate of change of base in time within (Eq, 2):

$\frac{1}{2}\cdot\frac{db}{dt}\cdot h = \frac{dA}{dt}-\frac{1}{2}\cdot b\cdot \frac{dh}{dt}$

$\frac{db}{dt} = \frac{2}{h}\cdot \frac{dA}{dt} -\frac{b}{h}\cdot \frac{dh}{dt}$ (Eq. 3)

The base of the triangle can be found clearing respective variable within (Eq. 1):

$b = \frac{2\cdot A}{h}$

If we know that $A = 130\,cm^{2}$ , $h = 15\,cm$ , $\frac{dh}{dt} = 2.5\,\frac{cm}{min}$ and $\frac{dA}{dt} = 4.7\,\frac{cm^{2}}{min}$ , the rate of change of the base of the triangle in time is:

$b = \frac{2\cdot (130\,cm^{2})}{15\,cm}$

$b = 17.333\,cm$

$\frac{db}{dt} = \left(\frac{2}{15\,cm}\right)\cdot \left(4.7\,\frac{cm^{2}}{min} \right) -\left(\frac{17.333\,cm}{15\,cm} \right)\cdot \left(2.5\,\frac{cm}{min} \right)$

$\frac{db}{dt} = -2.262\,\frac{cm}{min}$

The base of the triangle decreases at a rate of 2.262 centimeters per minute.

6 0

3 years ago

Please help me with this! Solve: 4+(−8+s)=204+(−8+s)=20 s=8s=8 s=16s=16 s=24s=24 s=−4