The only one i know is number 6 which the answer is 36
Corresponding sides in the triangles MOP and MNQ are
MO and MN,
OP and NQ,
PM and QM.
Ratios of the corresponding sides for similar triangles should be the same.
MQ/MP =MN/MO
MQ/(MQ+QP) = MN/(MN+NO)
5/(5+x) = 6/(6+18/5)
5*(6+18/5)=6(5+x)
30+18 = 30 +6x
18=6x
x=3 =QP
1-3 are about trigonometric ratios (SOH CAH TOA). 4, 5 are about the Law of Cosines, and 6 uses the Law of Sines.
1. Sin = Opposite/Hypotenuse
x = 10*sin(40°) ≈ 6.428
2. Sin = Opposite/Hypotenuse
x = arcsin(7/12) ≈ 35.69°
3. Tan = Opposite/Adjacent
x = 18/tan(52°) ≈ 14.063
4. b^2 = a^2 +c^2 -2ac*cos(B)
B = arccos((a^2 +c^2 -b^2)/(2ac)) = arccos((7^2 +13^2 -8^2)/(2*7*13))
B = arccos(11/13) ≈32.20°
5. Same formula.
x = √(a^2 +c^2 -2ab*cos(B)) = √(157-132cos(42°)) ≈ 7.675
6. The ratio of side lengths is the same as the ratio of the sines of the opposite angles.
6/10 = sin(x)/sin(100°)
x = arcsin((6/10)*sin(100°)) ≈ 36.22°
6 boxes of spaghettis for 20 persons so that means 12 boxes for 40 persons since there are 50 persons we have 10 persons left since 10 is equals to 20 divided by 2, divide 6 by 2 which is equals to 3 then add 12
Answer: 15