If we draw a rhombus OABC on a coordinate grid with one vertex at the point O (0,0)
and let its height be 1 then (using the Pythagoras theorem) the coordinates of the 4 points will be as follows:-
O = (0,0) , A = (1, 1), B = (sqrt2+ 1 , 1) , C = (sqrt2, 0)
Slope of the diagonal OB = 1 / (sqrt2 + 1)
Slope of the other diagonal AC = - 1 / (sqrt2 - 1)
Product of the slopes = - 1 / ( sqrt2 + 1)(sqrt2 - 1) = -1 / 1 = -1
This proves that the diagonals are perpendicular.
Answer:
a¹⁸b²⁴c⁵⁴
Step-by-step explanation:
(aᵇ)ᶜ = aᵇᶜ = aᵇ×ᶜ
(-aⁿ)ᵒᵈᵈ = -aⁿ
(-aⁿ)ᵉᵛᵉⁿ = aⁿ
aⁿ × aⁿ = aⁿ⁺ⁿ
_________
In this situation, 6 is an even exponent which means that the negative coefficient of this 9th degree monomial will be positive. Now the only step is to multiply the exponents by the exponent outside of the perenthesis which is 6.
so (-a³b⁴c⁹)⁶ = ((-a³)⁶(b⁴)⁶(c⁹)⁶) = ((a³ˣ⁶)(b⁴ˣ⁶)(c⁹ˣ⁶)) = ((a¹⁸)(b²⁴)(c⁵⁴)) = <em>a¹⁸b²⁴c⁵⁴</em>
Answer:
Option C: 6x-5y=15
Explanation:
y = -5/6x +8
8 is the <u>y-intercept</u>
-5/6x is the <u>slope</u>
when a slope is in <u>fraction form</u> the numerator is the y direction over the denominator how much the line changes in the x direction
::: (\_(\ Hope
*: (=' :') this
•.. (,('')('') helped :)
Answer:
-n
Step-by-step explanation:
Even though you have reflected this triangle, your side length would still be the same. Explanation: Reflection is when you take an object on your coordinate plain and put it somewhere else on the plain. So if side QR is 3 than side Q’R’ would also be 3. Hope this helps!
