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nasty-shy [4]
3 years ago
5

PQR is a right angled triangle with angle R 90 According to Pythagoras rule​

Mathematics
1 answer:
vazorg [7]3 years ago
3 0

Answer:

The Pythagorean Theorem states that a^2+b^2=c^2

Step-by-step explanation:

This formula applies to the side lengths and means that the length of leg "a" squared, plus the length of leg "b" squared, will equal the length of hypotenuse "c" squared. Please state a more specific question so I can go into more detail if you need it :)

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In ΔGHI, g = 27 cm, i = 35 cm and ∠I=63°. Find all possible values of ∠G, to the nearest degree.
tester [92]

Answer:43

Step-by-step explanation:

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3 years ago
B) Solve the following system of equations using Elimination Method:
faust18 [17]

Answer:

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Step-by-step explanation:

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3 years ago
Rearrange the following equations into the form y=mx+c
kifflom [539]

Answer:

a. y=5x-1

b. 2y=8-2x

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Step-by-step explanation:

there you go

5 0
3 years ago
A plane left 30 minutes late than its schedule time and in order to reach the destination 1500 km away in time it had to increas
schepotkina [342]
Let x= the usual speed
1500/x would equal how long it usually took the plane to read the destination
1500/(x+100) would equal how long it would take the plane now
So\frac{1500}{x} - \frac{1500}{x+100} =  \frac{1}{2} because it would lose 30 minutes already
Simplify:
\frac{1500(x+100)-1500x}{x(x+100)} =  \frac{1}{2}
\frac{1500x+150000-1500x}{x^2+100x} = \frac{1}{2}
\frac{150000}{x^2+100x} = \frac{1}{2}
\frac{300000}{x^2+100x} =1
300000= x^{2} +100x

x^2+100x-300000=0

x^2+600x-500x-300000=0

x(x+600)-500(x+600)

(x-500)(x+600)

x=500, x \neq -600


The usual speed was 500 hm/hr

7 0
3 years ago
Question 3 of 13
I am Lyosha [343]
\bold{ANSWER:}
OPTION B

\bold{SOLUTION:}

5 0
3 years ago
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