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Sunny_sXe [5.5K]

2 years ago

7

PLSSS HELP MY TEST IS ALMOST OVER

1 answer:

Ipatiy [6.2K]2 years ago

8 0

I think the answer is b

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What is the equation in point-slope form of a line that passes through the points (5, −3)(5, −3) and (−2, 9)(−2, 9) ?

Alina [70]

Point sloe is
y-y1=m(x-x1)
slope=m
a ponint is (x1,y1)

slope=(y2-y1)/(x2-x1)
(x,y)
(5,-3)
(-2,9)
slope=(9-(-3))/(-2-5)=12/-7=-12/7
m=-12/7

a point is (5,-3)
x1=5
y=-3
y-(-3)=-12/7(x-5)
y+3=-12/7(x-5)

2nd one

5 0

2 years ago

Simplify the expression

Slav-nsk [51]

First you need to combine like terms.

9x + 11y + 13

A coefficient is the number that comes before the variable (which is y).

The coefficient for y is 11.

Constants are the numbers that do not have variables attached to them.

The constant is 13.

Hope this helps!

5 0

3 years ago

Read 2 more answers

Solve for x and explain your answer

Dovator [93]

75+37=112. 180-112=68. 68-7=61. 61/5=12.2. so x=12.2

5 0

2 years ago

Keanu and Jeremy sold 25 boxes of popcorn for fundraiser Tiana so 60% of the boxes how many boxes did each cell

Simora [160]

Answer:

Tiana sold 15 boxes and Jeremy and Keanu sold 10

Step-by-step explanation:

60% of 25 = 15

25 - 15 is 10

This is the way I understand the problem.

7 0

2 years ago

A bridge in the shape of an arch connects two cities separated by a river. The two ends of the bridge are located at (–7, –13) a

sdas [7]

Answer:

$y=-\dfrac{13}{49}x^2$

Step-by-step explanation:

The shape of an arch corresponds to a parabola.

the general equation for a parabola is:

$y=ax^2+bx+c$

we're given three coordinates: (-7,-13),(7,-13) and (0,0)

so we can plug these values in the general equation to make 3 separate equations:

(x,y) = (-7,-13)

$-13=a(-7)^2+b(-7)+c$

$49a-7b+c=-13$

(x,y) = (7,-13)

$-13=a(7)^2+b(7)+c$

$49a+7b+c=-13$

(x,y) = (0,0)

$0=a(0)^2+b(7)+c$

$c=0$

so we have three equations. and we can solve them simultaneously to find the values of a,b, and c.

we've already found c = 0, let's use substitute it to other equations.

$49a-7b+c=-13\quad\Rightarrow\quad49a-7b=-13$

$49a+7b+c=-13\quad\Rightarrow\quad49a+7b=-13$

we can solve these two equation using the elimination method, by simply adding the two equations

$\quad\quad49a-7b=-13\\+\quad49a+7b=-13$

------------------------------

$\quad\quad 98a=-26$

$\quad\quad a=-\dfrac{13}{49}$

Now we can plug this value of a in any of the two equations.

$49a-7b=-13$

$49\left(-\dfrac{13}{49}\right)-7b=-13$

$-13-7b=-13$

$-7b=0$

$b=0$

We have the values of a,b, and c. We can plug them in the general equation to find the equation of the arch.

$y=\left(-\dfrac{13}{49}\right)x^2+0x+0$

$y=-\dfrac{13}{49}x^2$

$49y=-13x^2$

This our equation of the arch!

5 0

2 years ago