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Yuliya22 [10]
2 years ago
13

At a certain time of day, a 30-foot building casts a 10 foot shadow. How tall is a person who casts a 2 foot shadow?

Mathematics
2 answers:
ladessa [460]2 years ago
5 0

Answer: C

Step-by-step explanation:

6 feet

Anni [7]2 years ago
4 0

Answer:

C)  6 feet

Step-by-step explanation:

set up a proportion of height/shadow = height/shadow

30/10 = h/2

cross-multiply:

10h = 60

h = 6

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When an object is thrown upwards with a speed of 64 ft/sec, its height above the ground is given by the function h(t)=−16t2+64t
Svet_ta [14]

Answer:

The object will reach its highest point 0.5 seconds after it has been thrown.

Step-by-step explanation:

The object reaches its maximum height when velocity is equal to zero, the velocity is the derivative of function height. That is:

v(t) = \frac{d}{dt}h(t) (1)

Where v(t) is the velocity of the object at time t, in feet per seconds.

If we know that h(t) =-16\cdot t^{2}+64\cdot t and v(t) = 0\,\frac{ft}{s}, then the time when object reaches its highest point is:

v(t) = -32\cdot t+64

-32\cdot t + 64 = 0

t = 0.5\,s

The object will reach its highest point 0.5 seconds after it has been thrown.

3 0
2 years ago
D=rt solve the equation for the red variable which is T
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t=D/r

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4 0
3 years ago
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Someone please answer this
bonufazy [111]

Answer:

30.35

Step-by-step explanation:

Please mark me as brainliest it would mean a lot

3 0
3 years ago
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Answer:

-23

Step-by-step explanation:

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3 years ago
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