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True [87]
3 years ago
8

The length of a rectangle is 3 units shorter than one-third of the width, x.

Mathematics
1 answer:
AveGali [126]3 years ago
6 0

\frac{8x}{3} - 6 is the expression that represents the perimeter of rectangle

<em><u>Solution:</u></em>

Let "x" represent the width of rectangle

Given that length of rectangle is 3 units shorter than one-third of the width x

length of rectangle = one-third of the width x - 3

\text{ length of rectangle} = \frac{1}{3}x - 3 = \frac{x}{3} - 3\\\\\text{ length of rectangle} = \frac{x}{3} - 3

<em><u>The perimeter of rectangle is given as:</u></em>

<h3>perimeter of rectangle = 2(length + width)</h3>

Substituting the known values we get,

\text{ perimeter of rectangle }= 2(\frac{x}{3} - 3 + x)\\\\\rightarrow 2(\frac{x - 9 + 3x}{3})\\\\\rightarrow 2(\frac{4x-9}{3})\\\\\rightarrow\frac{8x-18}{3}\\\\\rightarrow\frac{8x}{3} - \frac{18}{3}\\\\\rightarrow\frac{8x}{3} - 6

Thus perimeter of rectangle is \frac{8x}{3} - 6

Thus option 1 is correct

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Answer:

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Step-by-step explanation:

The given function is

f(d)=-0.6d^2+5.4d+0.8

Where f(d) is the height of the ball at horizontal distance d.

Put f(d)=0, to find the distance where the ball touch the ground.

0=-0.6d^2+5.4d+0.8

Quadratic formula:

d=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Using the quadratic formula we get

d=\frac{-5.4\pm \sqrt{(5.4)^2-4(-0.6)(0.8)}}{2(-0.6)}

d=-0.146,9.146

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The distance can not be negative, therefore the ball remains in the air between d=0 to d=9.146.

9.146\approx 9.15

Therefore the correct option is D.

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The daily high temperature on October 31 in a certain city is normally distributed with µ = 50 and σ = 8 . What is the probabili
tatyana61 [14]

Answer:

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Step-by-step explanation:

µ = 50

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We are supposed to find the probability that the high temperature on October 31 in a randomly chosen year will be between 46 degrees and 58 degrees

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Formula : Z=\frac{x-\mu}{\sigma}

at x = 46

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Refer the z table for p value

p value = 0.3085

at x = 58

Z=\frac{58-50}{8}

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Refer the z table for p value

p value = 0.8413

P(46 < x< 58)=P(x

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Distance between Train 1 and Train 2 = 95 miles.
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9514 1404 393

Answer:

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Step-by-step explanation:

The time is found from ...

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The trains will meet after 19/21 hours, about 54 minutes, 17 seconds.

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