The lengths of HJ and JK are 50 and 72 respectively.
Given: J is between H and K. the length of HJ=2x+4, JK=3x+3, and HK=22.
The line HJ and JK are collinear then the total length is given as: HJ+JK=HK
substitute values
⇒ (2x+4)+(3x+3)=22
⇒ 5x+7=22
⇒ 5x=22-7
⇒ 5x=15
⇒ x=3
Thus, the length of HJ is (2x+4)=(2*3+4)=10
And the length of JK is (3x+3)=(3*3+3)=12
Learn more about collinear lines here: brainly.com/question/27943430
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The lost percentage is 25%
The percentage remaining is 75%
- Thanks
- ThanksHope it helps
Answer:
-46
Step-by-step explanation:
4 - 2(a^2 – b^2)^2 =
= 4 - 2(3^2 – 2^2)^2
= 4 - 2(9 - 4)^2
= 4 - 2(5)^2
= 4 - 2(25)
= 4 - 50
= -46
Pythagorean Theorem
x^2 = 15.7^2 -7.8^2
x^2 =
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185.65
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x =
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13.6253440324
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Answer is C
