All categories

3 years ago

Need help with this geometry work show work hard for me pls answer fast due now

Mathematics

1 answer:

kati45 [8]3 years ago

4 0

Answer:

3) answer is 120 4) 105

Step-by-step explanation

3) 180 - (70+50) = 60

180-60 = 120 <-- thats the answer

4) 180 - ( 80+25) = 75

180 - 75 = 105 < thats the answer

You might be interested in

Find the unit rate. <br><br> 5/8 mile in 1/4 hour

ivolga24 [154]

Answer:

5/8 : 1/4 :: m : 1 proportion

5/8 = m/4 product means/extremes

5/2 = m

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Mari and Jen each work 20 hours a week at different jobs. Mari earns twice as much as Jen. Together they earn $480. How much doe

Salsk061 [2.6K]

We will call:
M=Mari
J=Jen

Initial equations:

M=2J
M+J=480
(the fact that they work 20 hours a week is not needed in this problem information)

Plug in:
2J+J=480
3J=480
J=160

Jen makes $160 a week.

Therefore:

M=2J
M=2(160)
M=320

Mari makes $320 per week
Jen makes $160 per week

7 0

3 years ago

Here are the monthly charges for Jo's mobile phone

yaroslaw [1]

Answer:

The correct answer is - 625.36.

Step-by-step explanation:

Given:

Fixed mothly plan - 616

free minutes - 150

Used minutes - 170

Free text - 150

Used text - 182

Charging amount over free limit - 18p

Solution:

Number of minutes over the limit - 170 - 150 = 20

Number of text over the limit - 182 - 150 = 32

So the extra amount that will be add to the monthly charge would be -

(20*0.18) +(32*0.18)

and the total charge of the month would be -

= 616+(20*0.18) +(32*0.18)

= 616+3.60+5.76

= 625.36

Thus, the correct answer would be - 625.36

5 0

3 years ago

Add the product of (-16) and (-9) to the quotient of (-132) by 6.

alukav5142 [94]

9*16-132/6=122...........

8 0

2 years ago

Find all the complex roots. Write the answer in exponential form.

dezoksy [38]

We have to calculate the fourth roots of this complex number:

$z=9+9\sqrt[]{3}i$

We start by writing this number in exponential form:

$\begin{gathered} r=\sqrt[]{9^2+(9\sqrt[]{3})^2} \\ r=\sqrt[]{81+81\cdot3} \\ r=\sqrt[]{81+243} \\ r=\sqrt[]{324} \\ r=18 \end{gathered}$ $\theta=\arctan (\frac{9\sqrt[]{3}}{9})=\arctan (\sqrt[]{3})=\frac{\pi}{3}$

Then, the exponential form is:

$z=18e^{\frac{\pi}{3}i}$

The formula for the roots of a complex number can be written (in polar form) as:

$z^{\frac{1}{n}}=r^{\frac{1}{n}}\cdot\lbrack\cos (\frac{\theta+2\pi k}{n})+i\cdot\sin (\frac{\theta+2\pi k}{n})\rbrack\text{ for }k=0,1,\ldots,n-1$

Then, for a fourth root, we will have n = 4 and k = 0, 1, 2 and 3.

To simplify the calculations, we start by calculating the fourth root of r:

$r^{\frac{1}{4}}=18^{\frac{1}{4}}=\sqrt[4]{18}$

<em>NOTE: It can not be simplified anymore, so we will leave it like this.</em>

Then, we calculate the arguments of the trigonometric functions:

$\frac{\theta+2\pi k}{n}=\frac{\frac{\pi}{2}+2\pi k}{4}=\frac{\pi}{8}+\frac{\pi}{2}k=\pi(\frac{1}{8}+\frac{k}{2})$

We can now calculate for each value of k:

$\begin{gathered} k=0\colon \\ z_0=\sqrt[4]{18}\cdot(\cos (\pi(\frac{1}{8}+\frac{0}{2}))+i\cdot\sin (\pi(\frac{1}{8}+\frac{0}{2}))) \\ z_0=\sqrt[4]{18}\cdot(\cos (\frac{\pi}{8})+i\cdot\sin (\frac{\pi}{8}) \\ z_0=\sqrt[4]{18}\cdot e^{i\frac{\pi}{8}} \end{gathered}$ $\begin{gathered} k=1\colon \\ z_1=\sqrt[4]{18}\cdot(\cos (\pi(\frac{1}{8}+\frac{1}{2}))+i\cdot\sin (\pi(\frac{1}{8}+\frac{1}{2}))) \\ z_1=\sqrt[4]{18}\cdot(\cos (\frac{5\pi}{8})+i\cdot\sin (\frac{5\pi}{8})) \\ z_1=\sqrt[4]{18}e^{i\frac{5\pi}{8}} \end{gathered}$ $\begin{gathered} k=2\colon \\ z_2=\sqrt[4]{18}\cdot(\cos (\pi(\frac{1}{8}+\frac{2}{2}))+i\cdot\sin (\pi(\frac{1}{8}+\frac{2}{2}))) \\ z_2=\sqrt[4]{18}\cdot(\cos (\frac{9\pi}{8})+i\cdot\sin (\frac{9\pi}{8})) \\ z_2=\sqrt[4]{18}e^{i\frac{9\pi}{8}} \end{gathered}$ $\begin{gathered} k=3\colon \\ z_3=\sqrt[4]{18}\cdot(\cos (\pi(\frac{1}{8}+\frac{3}{2}))+i\cdot\sin (\pi(\frac{1}{8}+\frac{3}{2}))) \\ z_3=\sqrt[4]{18}\cdot(\cos (\frac{13\pi}{8})+i\cdot\sin (\frac{13\pi}{8})) \\ z_3=\sqrt[4]{18}e^{i\frac{13\pi}{8}} \end{gathered}$

Answer:

The four roots in exponential form are

z0 = 18^(1/4)*e^(i*π/8)

z1 = 18^(1/4)*e^(i*5π/8)

z2 = 18^(1/4)*e^(i*9π/8)

z3 = 18^(1/4)*e^(i*13π/8)

5 0

1 year ago