Given:
The polynomials are:
![3x^2y^2-2xy^5](https://tex.z-dn.net/?f=3x%5E2y%5E2-2xy%5E5)
![-3x^2y^2+3x^2y^2+3x^4y](https://tex.z-dn.net/?f=-3x%5E2y%5E2%2B3x%5E2y%5E2%2B3x%5E4y)
To find:
The completely simplified sum of the polynomials.
Solution:
We have,
![3x^2y^2-2xy^5](https://tex.z-dn.net/?f=3x%5E2y%5E2-2xy%5E5)
![-3x^2y^2+3x^2y^2+3x^4y](https://tex.z-dn.net/?f=-3x%5E2y%5E2%2B3x%5E2y%5E2%2B3x%5E4y)
The sum of given polynomials is:
![Sum=3x^2y^2-2xy^5-3x^2y^2+3x^2y^2+3x^4y](https://tex.z-dn.net/?f=Sum%3D3x%5E2y%5E2-2xy%5E5-3x%5E2y%5E2%2B3x%5E2y%5E2%2B3x%5E4y)
![Sum=-2xy^5+3x^4y+3x^2y^2](https://tex.z-dn.net/?f=Sum%3D-2xy%5E5%2B3x%5E4y%2B3x%5E2y%5E2)
Therefore, the sum of the given polynomials is
. It is a polynomial with degree 6 and leading coefficient -2.
Answer: 84.728
Step-by-step explanation: 105.91•.20=21.182
105.91-21.182=84.728
If you have any questions just ask
Because this is a right angle triangle, we can use the Pythagorean theorem to find the missing leg.
The Pythagorean theorem is this:
![a^{2} + b^{2} = c^{2}](https://tex.z-dn.net/?f=%20a%5E%7B2%7D%20%2B%20b%5E%7B2%7D%20%3D%20c%5E%7B2%7D%20%20)
The Pythagorean theorem tells us if you square both the legs then add them up together, you will get the length of the hypotenuse squared.
We know one leg is 24 and the hypotenuse is 26. Plug them into the equation.
24^2 + b^2 = 26^2
Solve for b.
24^2 + b^2 = 26^2
576 + b^2 = 26^2
576 + b^2 = 676
b^2 = 100
Take the square root of both sides.
b = 10
So, the other leg of the triangle is 10 units long.
Answer:
8
Step-by-step explanation:
![\frac{x}{14} = \frac{40}{70} \\ x = \frac{40}{70} \times 14 \\ x = \frac{40}{10} \times 2 \\ x = 4 \times 2 \\ x = 8](https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%7D%7B14%7D%20%20%3D%20%20%5Cfrac%7B40%7D%7B70%7D%20%20%5C%5C%20x%20%3D%20%20%5Cfrac%7B40%7D%7B70%7D%20%20%5Ctimes%2014%20%5C%5C%20x%20%3D%20%20%5Cfrac%7B40%7D%7B10%7D%20%20%5Ctimes%202%20%5C%5C%20x%20%3D%204%20%5Ctimes%202%20%5C%5C%20x%20%20%3D%208)