Answer:
a.The classification error rate for records that are truly fraudulent: By increasing the cutoff value, the non-fraudulent records will go down and this increases the error rate.
Also, if the cutoff value is down, the fraudulent records will increase and this lowers the error rate
.b.The classification error rate for records that are truly non-fraudulent: By moving up the cutoff value, the fraudulent records will go down and this decreases the error rate.
Also, if the cutoff value is down, the non-fraudulent records will go down and this increases the error rate.
Answer:132 combinations
Step-by-step explanation:
Step-by-step explanation:
Assuming the data is as shown, restaurant X has a mean service time of 180.56, with a standard deviation of 62.6.
The standard error is SE = s/√n = 62.6/√50 = 8.85.
At 95% confidence, the critical value is z = 1.960.
Therefore, the confidence interval is:
180.56 ± 1.960 × 8.85
180.56 ± 17.35
(163, 198)
Restaurant Y has a mean service time of 152.96, with a standard deviation of 49.2.
The standard error is SE = s/√n = 49.2/√50 = 6.96.
At 95% confidence, the critical value is z = 1.960.
Therefore, the confidence interval is:
152.96 ± 1.960 × 6.96
152.96 ± 13.64
(139, 167)
Answer:
A.200
Step-by-step explanation:
Answer:
x=-4
Step-by-step explanation:
x+12=8
x=8-12
Andre did not multiple both by four to get the exact whole number. He also, didnt subtract 12 which is not possible due to it being multiplied by 1/4.