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3 years ago

What is the area of the figure ?

Mathematics

1 answer:

vodka [1.7K]3 years ago

5 0

Answer:

48cm^2

Step-by-step explanation:

We can break the composite figure into two pieces.

We take the bottom rectangle and determine its area

The figure is 10 cm by 2 cm

A = 10*2 = 20cm^2

The height of the vertical rectangle is 9 cm -2 cm = 7 cm

The width is 10 cm - 6 cm = 4 cm

The figure is 7 cm cm by 4 cm

A = 7*4 = 28cm^2

The total area is the sum of the two areas

20 cm^2 + 28 cm^2 = 48 cm^2

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no it not really the same

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3 years ago

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Step-by-step explanation:

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3 years ago

What is the probability of drawing the compliment of a king or a

inna [77]

Answer:

The probability of drawing the compliment of a king or a queen from a standard deck of playing cards = 0.846

Step-by-step explanation:

Step(i):-

Let 'S' be the sample space associated with the drawing of a card

n (S) = 52C₁ = 52

Let E₁ be the event of the card drawn being a king

$n( E_{1} ) = 4 _{C_{1} } = 4$

Let E₂ be the event of the card drawn being a queen

$n( E_{2} ) = 4 _{C_{1} } = 4$

But E₁ and E₂ are mutually exclusive events

since E₁ U E₂ is the event of drawing a king or a queen

step(ii):-

The probability of drawing of a king or a queen from a standard deck of playing cards

P( E₁ U E₂ ) = P(E₁) +P(E₂)

$= \frac{4}{52} + \frac{4}{52}$

P( E₁ U E₂ ) = $\frac{8}{52}$

step(iii):-

The probability of drawing the compliment of a king or a queen from a standard deck of playing cards

$P(E_{1}UE_{2}) ^{-} = 1- P(E_{1} U E_{2} )$

$P(E_{1}UE_{2}) ^{-} = 1- \frac{8}{52}$

$P(E_{1}UE_{2}) ^{-} = \frac{52-8}{52} = \frac{44}{52} = 0.846$

Conclusion:-

The probability of drawing the compliment of a king or a queen from a standard deck of playing cards = 0.846

5 0

3 years ago

40 POINTS!!!!!!!!!!!!!!!!!!!!!!!!!!!!! HELPPPPPPPP!!!

Dmitrij [34]

School to mall - 16 miles
mall to library - 30 miles

16²+30²=X²
256+900=X²
X²=1156
X=34

16+30=46
hypotenuse = 34
46-34=12
So Mike travel 12 miles more.

5 0

3 years ago

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