Answer:
Center = (5,-3) and radius = 7
Step-by-step explanation:
(5) If Oskar bisects the diameter of a circle, what is he trying to construct the radius of the circle.
(6) The given equation is :

The general equation of circle is given by :
...(1)
Where
(a,b) are the coordinates of the centre and r is the radius.
The given equation can be written as :
..(2)
Comparing equation (1) and (2) we get :
a = 5, b = -3 and r = 7
So,
Center = (5,-3) and radius = 7
Hence, this is the required solution.
A relation is any set of ordered pairs, which can be thought of as (input, output).
A function is a relation in which NO two ordered pairs have the same first component and different second components.
The set of first components (x-coordinates) in the ordered pairs is the DOMAIN of the relation.
The set of second components (y-coordinates) is the RANGE of the relation.
Part 1:
Domain: {-1, 1, 3, 6}
Range: {2, 2, 2, 2}
Part 2:
To determine whether the given relation represents a function, look at the given relation and ask yourself, “Does every first element (or input) correspond with EXACTLY ONE second element (or output)?”
Remember that a function can only take on 1 output for each input.
It helps to plot the points on the graph and perform the Vertical Line Test (VLT):
The Vertical Line Test allows us to know whether or not a graph is actually a function. If a vertical line intersects the graph in all places at exactly one point, then the relation is a function.
As you can see in the attached screenshot, every vertical line drawn only has 1 point in it. This means that each x-value corresponds to exactly one y-value. The given relation passed the VLT. Therefore, the relation is a function.
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Answer:
It is already solved!
Step-by-step explanation:
It is meant to be in y = mx + b form where x is the slope and b is is the y-intercept.
The predicted value of the car in the year 2006 to the nearest dollar would be $651.
<h3>What is the predicted value of the car?</h3>
The first step is to determine the rate of depreciation
g = (FV/PV)^(1/n) - 1
Where:
FV = value of the car in 2001
PV = value of the car in 1993
n = number ofyears = 8
(2700/26,300)^(1/8) - 1 = -24.76%
Now determine the value of the car in 2006
2700x ( 1 - 0.2476)^5 = $651
To learn more about depreciation, please check: brainly.com/question/25552427