Answer:
is outside the circle of radius of 
centered at 
.
Step-by-step explanation:
Let 
and 
denote the center and the radius of this circle, respectively. Let 
be a point in the plane.
Let 
denote the Euclidean distance between point and point .
In other words, if is at 
while is at 
, then 
.
Point would be inside this circle if 
. (In other words, the distance between 
and the center of this circle is smaller than the radius of this circle.)
Point would be on this circle if 
. (In other words, the distance between and the center of this circle is exactly equal to the radius of this circle.)
Point would be outside this circle if 
. (In other words, the distance between and the center of this circle exceeds the radius of this circle.)
Calculate the actual distance between and :
.
On the other hand, notice that the radius of this circle, 
, is smaller than . Therefore, point would be outside this circle.
Answer:
The 3rd term is
Step-by-step explanation:
From the given information, the first term of the sequence is
The common ratio of the sequence is
The explicit formula for a geometric sequence is :
To find the third term, we put n=3 to get:
This simplifies to:
There is no real shortcut in learning integration formulas. You should take time learning and understanding how the formulas are derived until you are familiar with the formulas and you can easily recall the formulas. Hope this answers the question.
Answer: 0.5714
Step-by-step explanation:
Answer:
-14
Step-by-step explanation:
a·b = |a|×|b|×cos(angle between them)
= 4×7×(-1/2)
= -14
