All categories

3 years ago

HELP ASAP!!! EASY POINTS!!!!

Mathematics

2 answers:

Marina CMI [18]3 years ago

4 0

(y-y1)=m(x-x1)

(y-2)=3(x--1)

y=3x--3+2

y=3x+5

3x-y+5=0

notka56 [123]3 years ago

3 0

Answer:

$y-2=3(x+1)$

Step-by-step explanation:

The point-slope formula is $y -y_{1} =m(x -x_{1})$ where we substitute a point (x,y) for $(x_{1},y_{1})$ .

We have m=3 and (-1, 2). We input m and $x_{1} =-1\\y_{1}=2$ .

$y-2=3(x-(-1))\\y-2=3(x+1)$

You might be interested in

(4x³-5x+10) ÷ (x+1)

zlopas [31]

Answer:

4x^2 − 4x −1 + 11 / x+1

Step-by-step explanation:

The answer is

4x^2 − 4x −1 + 11 / x+1

4 0

3 years ago

Read 2 more answers

Can someone help me with this question?

Andrei [34K]

Answer:

I don’t know what 14 and 15 are but I know 16 is 6 ft

Step-by-step explanation:

3 0

3 years ago

A high school drama teacher organizes a musical production

NeX [460]

Yes she does, shes also a great teacher for putting in the work for the production if the play.

3 0

2 years ago

A cellular phone company monitors monthly phone usage. The following data represent the monthly phone use in minutes of one part

Sergeu [11.5K]

Answer:

The standard deviation increased but there was no change in the interquantile range

Step-by-step explanation:

We are given the following data in the question:

320, 411, 348, 537, 420, 449, 462, 403, 454, 517, 515, 358, 438, 541, 387, 368, 502, 437, 431, 428.

n = 20

a) Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{8726}{20} = 436.3$

Sum of squares of differences =

13525.69 + 640.09 + 7796.89 + 10140.49 + 265.69 + 161.29 + 660.49 + 1108.89 + 313.29 + 6512.49 + 6193.69 + 6130.89 + 2.89 + 10962.09 + 2430.49 + 4664.89 + 4316.49 + 0.49 + 28.09 + 68.89 = 75924.2

$S.D = \sqrt{\frac{75924.2}{19}} = 63.21$

Sorted Data = 320, 348, 358, 368, 387, 403, 411, 420, 428, 431, 437, 438, 449, 454, 462, 502, 515, 517, 537, 541

$IQR = Q_3 - Q_1\\Q_3 = \text{upper median},\\Q_1 = \text{ lower median}$

$Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}$

$Median = \frac{431 + 437}{2} = 434$

$Q_1 = \frac{387 + 403}{2} = 395\\\\Q_3 = \frac{462 + 502}{2} = 482$

IQR = $482 - 395 = 87$

b) After changing the observation

0, 411, 348, 537, 420, 449, 462, 403, 454, 517, 515, 358, 438, 541, 387, 368, 502, 437, 431, 428

$Mean =\displaystyle\frac{8406}{20} = 420.3$

Sum of squares of differences =

176652.09 + 86.49 + 5227.29 + 13618.89 + 0.09 + 823.69 + 1738.89 + 299.29 + 1135.69 + 9350.89 + 8968.09 + 3881.29 + 313.29 + 14568.49 + 1108.89 + 2735.29 + 6674.89 + 278.89 + 114.49 + 59.29 = 247636.2

$S.D = \sqrt{\frac{247636.2}{19}} = 114.16$

Sorted Data = 0, 348, 358, 368, 387, 403, 411, 420, 428, 431, 437, 438, 449, 454, 462, 502, 515, 517, 537, 541

$Median = \frac{431 + 437}{2} = 434$

$Q_1 = \frac{387 + 403}{2} = 395\\\\Q_3 = \frac{462 + 502}{2} = 482$

IQR = $482 - 395 = 87$

Thus. the standard deviation increased but there was no change in the interquantile range.

5 0

3 years ago

The lengths of the sides of the triangle are 13cm, 14 cm, and 15 cm. Is the triangle a right triangle?

Helga [31]

Answer:

No, it is not a right triangle.

Step-by-step explanation:

If the triangle was a right triangle, then the Pythagorean Theorem states that a^2 + b^2 = c^2. Let's test it on this triangle:

13^2 + 14^2 = 365, or c^2. If this is a right triangle, c should equal 15.

However, sqrt(365) = 19.1, which is not 15. So, the triangle is not a right triangle.

4 0

3 years ago