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DiKsa [7]
4 years ago
8

Twice a number (x) is less than 12 plz helpp

Mathematics
2 answers:
salantis [7]4 years ago
6 0
The answer to this is 2x<12
masya89 [10]4 years ago
5 0

the answer is 2x < 12

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Find the most common factor of 120 and 300
Nadusha1986 [10]
Answer: 60

Greatest common factor of 120 = 60
And since 60 is also a common factor of 300 it is the greatest common factor of both numbers.

Hope this helps :)
8 0
3 years ago
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What is an equivalent expression of -5r+8r+5
rjkz [21]
The answer is. 3r + 5
6 0
4 years ago
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Which fraction is equivalent to a repeating decimal? A. 1/8 B. 2/8 C. 14/21 D. 3/10​
saveliy_v [14]

Answer:

C

Step-by-step explanation:

14/21 = 2/3 = .666666666666666666666.....7

3 0
3 years ago
Given a normal population whose mean is 675 and whose standard deviation is 44, find each of the following: A. The probability t
NNADVOKAT [17]

Answer:

27.88% probability that a random sample of 5 has a mean between 677 and 693.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 675, \sigma = 44, n = 5, s = \frac{44}{\sqrt{5}} = 19.6774

The probability that a random sample of 5 has a mean between 677 and 693.

This is the pvalue of Z when X = 693 subtracted by the pvalue of Z when X = 677. So

X = 693

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{693 - 675}{19.6774}

Z = 0.91

Z = 0.91 has a pvalue of 0.8186

X = 677

Z = \frac{X - \mu}{s}

Z = \frac{677 - 675}{19.6774}

Z = 0.1

Z = 0.1 has a pvalue of 0.5398

0.8186 - 0.5398 = 0.2788

27.88% probability that a random sample of 5 has a mean between 677 and 693.

5 0
4 years ago
Rhett put up nine posters in his neighborhood and handed out fliers at a local grocery store each with a photo of his lost puppy
Pani-rosa [81]

D. y=20x+18

Step-by-step explanation:

First, there are 9 posters each costing $2 to post, so 2x9=18

Secondly, it costs $0.20 per flier to print, but we don't have the exact amount of fliers that Rhett printed, instead the equation asks to use x.

Lastly, it would all come together to add up to y(the total amount of money Rhett spent)

5 0
3 years ago
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