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4 years ago

What is an equivalent expression of -5r+8r+5

2 answers:

7 0

If you simplify it more and combine the like terms which are -5r and 8r it will be 3r; and then the left over 5 can be added. 3r+5

rjkz [21]4 years ago

6 0

The answer is. 3r + 5

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Help me with this please!!

Mamont248 [21]

Answer: (2,7)

Midpoint formula = ( $\frac{x1,x2}{2}$ , $\frac{y1,y2}{2}$ )

1 + 3 / 2 = 2

5 + 9 / 2 = 7

7 0

3 years ago

Evaluate the function rule to find the range of each function for the domain {-3, 0, 5}. f(x) = x² − 6x + 4

harina [27]

Range is output for given input

domain is D={-3,0,5}
input -3,0 and 5 for x

f(-3)=(-3)^2-6(-3)+4
f(-3)=9+18+4
f(-3)=31

F(0)=(0)^2-6(0)+4

f(0)=0-0+4

f(0)=4

f(5)=(5)^2-6(5)+4

f(5)=25-30+4

f(5)=-1

Domain={-3,0,5}

Range={31,4,-1}

5 0

3 years ago

Don't stress anymore I'm here to help in online mathematics classes I have a doctorate degree in maths

frosja888 [35]

Then I'll definitely will ask you questions about maths :)

7 0

3 years ago

Read 2 more answers

True or False?<br><br> The output values are the x-coordinates.

kap26 [50]

False. it would be y.

6 0

3 years ago

Read 2 more answers

Which equations represent the line that is perpendicular to the line 5x − 2y = −6 and passes through the point (5, −4)? Select t

Pepsi [2]

Answer:

Step-by-step explanation:

Two lines are perpendicular if the first line has a slope of $m$ and the second line has a slope of $\frac{1}{-m}$ .

With this information, we first need to figure out what the slope of the line is that we're given, and then we can determine what the slope of the line we're trying to find is:

$5x - 2y = -6$

$-2y = -5x - 6$

$y = \frac{5}{2}x + 3$

We now know that $m = \frac{5}{2}$ for the first line, which means that the slope of the second line is $m = \frac{-2}{5}$ . With this, we have the following equation for our new line: