Note: The height of the room must be 3 m instead of 3 cm because 3 cm is too small and it cannot be the height of a room.
Given:
Perimeter of the floor of a room = 18 metre
Height of the room = 3 metre
To find:
The area of 4 walls of the room.
Solution:
We know that, the area of 4 walls of the room is the curved surface area of the cuboid room.
The curved surface area of the cuboid is
Where, h is height, l is length and b is breadth.
Perimeter of the rectangular base is 2(l+b). So,
Putting the given values, we get
Therefore, the area of 4 walls of the room is 54 sq. metres.
Answer: A. There all 90 degrees
Step-by-step explanation:
Given: Three parallel lines are cut by a transversal and one angle is measured to be 90 degrees.
We know that if two lines cut by transversal the following pairs are equal:
- Vertically opposite angles.
- Corresponding angles.
- Alternate interior angles.
- Alternate exterior angles.
If one angles measures 90°, then its supplement would be 90°.
Then by using above properties , we will get measure of all angles as 90°.
Answer:
n < 20
Step-by-step explanation:
2n – 1 < 39
Add 1 to each side
2n – 1+1 < 39+1
2n < 40
Divide each side by 2
2n/2 < 40/2
n < 20
9m+14=2m
9m-2m= -14
7m = -14
m= -2
to check: u need to chance the m to -2
9m - 2m= -14
9 × -2= -18
-2 × -2= -4
-18 - (-4)= -14
i think is right
Answer:
Step-by-step explanation:
-3x + 4y = -18
8x - 4y = 28
5x = 10
x = 2
4 - y = 7
-y = 3
y = -3
(2, -3)
