Answer:where’s the number line?
Step-by-step explanation:
I tried solving it, and there is no solution
Answer:
13\left(13a^{2}-4a-5b-15b^{2}\right)
Step-by-step explanation:
factored 13

When you factor a quadratic ax² + bx + c, it becomes (x+m)(x+n), where mn = ac, and m+n = b.
In x²+x-6, we want to find two numbers that multiply to -6 and add to 1.
3 and -2 satisfy both of these criteria, so there are our factors.

In x²-7x+10, we want to find two numbers that multiply to 10 and add to -7.
-5 and -2 satisfy both of these criteria, so there are our factors.

The (x-2) cancels and we're left with
Would have to go with x=5