The solution of the given equation is -6 and 1.
<h3>What is Quadratic Equation?</h3>
A quadratic equation is an algebraic equation of the second degree in x. The quadratic equation in its standard form is ax² + bx + c = 0, where a and b are the coefficients, x is the variable, and c is the constant term.
Here, given equation:
(x+2)(x+3) = 12
x(x+3)+2(x+3) = 12
x² + 3x + 2x + 6 = 12
x² + 5x + 6 - 12 = 0
x² + 5x - 6 = 0
x² + 6x - x - 6 = 0
x(x+6) -1(x+6) = 0
(x+6)(x-1) = 0
Now, x + 6 = 0 or x - 1 = 0
x = -6 or x = 1
Thus, the solution of the given equation is -6 and 1.
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Answer:
he can buy 5!
Step-by-step explanation:
50.30 * 5 = 251.5
if you add another hat it will be more than $300
The net change between the given values of the variable is 6a - 6
<h3>How to determine the net change between the given values of the variable?</h3>
The given parameters are
g(x) = 6x
Where
x = 1 and x =a
Calculate g(1) and g(a)
So, we have
g(1) = 6 * 1
g(1) = 6
g(a) = 6 * a
g(a) = 6a
The net change between the given values of the variable is
Change = g(a) - g(1)
So, we have
Change = 6a - 6
Hence, the net change between the given values of the variable is 6a - 6
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Answer:
x = -2+√3i and -2-√3i
Step-by-step explanation:
The formula for the general formula is expressed as;
x = -b±√b²-4ac/2a
Given the expression
x²+4x+7 = 0
a = 1, b = 4 and c = 7
Substitute
x = -4±√4²-4(1)(7)/2(1)
x = -4±√16-28/2
x = -4±√-12/2
x = -4±√4*-3/2
x = -4±2√-3/2
x = -4±2√3i/2
x = -4+2√3i/2 and -4-2√3/2
x = -2+√3i and -2-√3i
Answer:
1yr 47,000, 2nd yr 48,880, 3rd yr 51,617.28, 4th yr 57,346.7981 or 57,346.80
Step-by-step explanation:
1yr 47,000
2nd yr 47,000 x 4% = 48,880
3rd yr 48,880 x 5.6% = 51,617.28
4th yr 51,617.28 x 11.1% = 57,346.7981 or 57,346.80
