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Whitepunk [10]
4 years ago
9

An airplane flies at 250 mph. How far will it travel in 5 hours at that rate of speed?

Mathematics
2 answers:
Paul [167]4 years ago
4 0
1250 miles. You're given a rate and a time, so you can solve for distance using d =rt
d= 250*5 = 1250
GarryVolchara [31]4 years ago
4 0
To find this, you have to multiply the mph by the hours.
250x5=1250 so your answer is 1250miles
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An alarming number of U.S. adults are either overweight or obese. The distinction between overweight and obese is made on the ba
madreJ [45]

Answer:

(A) The probability that a randomly selected adult is either overweight or obese is 0.688.

(B) The probability that a randomly selected adult is neither overweight nor obese is 0.312.

(C) The events "overweight" and "obese" exhaustive.

(D) The events "overweight" and "obese" mutually exclusive.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = a person is overweight

<em>Y</em> = a person is obese.

The information provided is:

A person is overweight if they have BMI 25 or more but below 30.

A person is obese if they have BMI 30 or more.

P (X) = 0.331

P (Y) = 0.357

(A)

The events of a person being overweight or obese cannot occur together.

Since if a person is overweight they have (25 ≤ BMI < 30) and if they are obese they have BMI ≥ 30.

So, P (X ∩ Y) = 0.

Compute the probability that a randomly selected adult is either overweight or obese as follows:

P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)\\=0.331+0.357-0\\=0.688

Thus, the probability that a randomly selected adult is either overweight or obese is 0.688.

(B)

Commute the probability that a randomly selected adult is neither overweight nor obese as follows:

P(X^{c}\cup Y^{c})=1-P(X\cup Y)\\=1-0.688\\=0.312

Thus, the probability that a randomly selected adult is neither overweight nor obese is 0.312.

(C)

If two events cannot occur together, but they form a sample space when combined are known as exhaustive events.

For example, flip of coin. On a flip of a coin, the flip turns as either Heads or Tails but never both. But together the event of getting a Heads and Tails form a sample space of a single flip of a coin.

In this case also, together the event of a person being overweight or obese forms a sample space of people who are heavier in general.

Thus, the events "overweight" and "obese" exhaustive.

(D)

Mutually exclusive events are those events that cannot occur at the same time.

The events of a person being overweight and obese are mutually exclusive.

5 0
3 years ago
Barbara, Mark, and Carlos participated in the third heat of “The Big Race”. Barbara thought she could win with a 3 meter head st
steposvetlana [31]
Distance to travel = 20 m.
Let us determine the time, t, that each participant took to complete 20 m.

Barbara:
Average speed = (3 m)/(2 s) = 1.5 m/s
t = 20/1.5 = 13.3 s

Mark:
t =  5 s

Carlos:
y = x + 1
where
y = 20 m
x = time, t
Therefore
t =x = y - 1 = 20 - 1 = 19 s

Summary:
Barbara:  13.3 s
Mark:       5 s
Carlos:     19 s

Answer:
The winner is Mark
7 0
4 years ago
Over the last 6 months, Josh wrote 6 checks for a total of $702 to pay his phone bill. His phone bill is the same amount each mo
algol13

Answer:

C

Step-by-step explanation:

702divded by 6=117

hes taking away

8 0
3 years ago
Read 2 more answers
(T+10.5) + 2t + 90 = 180
Masja [62]

Answer:

x = 26.5

Step-by-step explanation:

Step 1: Write equation

(t + 10.5) + 2t + 90 = 180

Step 2: Solve for <em>t</em>

<u>Combine like terms:</u> 3t + 100.5 = 180

<u>Subtract 100.5 on both sides:</u> 3t = 79.5

<u>Divide both sides by 3:</u> t = 26.5

Step 3: Check

<em>Plug in x to verify it's a solution.</em>

<u>Substitute:</u> (26.5 + 10.5) + 2(26.5) + 90 = 180

<u>Parenthesis:</u> 37 + 56 + 90 = 180

<u>Add:</u> 180 = 180

∴ x = 26.5

5 0
4 years ago
Read 2 more answers
How is 600:450 and 4:3 equalivent
romanna [79]

Answer:

when you simplify 600:450 to the smallest it can be, its 4:3. For proof, multiply 4:3 by 150. 4 times 150 is 600 and 3 times 150 is 450.

5 0
3 years ago
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