Question

Steve takes 6 hours to get the yard work done by himself. If Bill works alone, it takes him 10 hours. How long would it take them working together to do all of the yard work?

Answer 1

How much work is done in an hour by each:
s = 1/6 of the yard in one hourb = 1/10 of the yard in an hour
working together they can do:
1/6 + 1/10 in an hour; or 16/60; we can invert this number to determine how long it takes to finish the yard
60/16 hours

=3 hours and 45 minutes

Answer 2

Answer:

In 3 hour 45 minutes Both working together do all of yard work.

Step-by-step explanation:

Time taken by Steve to do yard work = 6 hours

Work Done by Steve in a hour = $\frac{1}{6}$

Time taken by Bill to do yard work = 10 hours

Work Done by Steve in a hour = $\frac{1}{10}$

Work done by both in a hour = $\frac{1}{6}+\frac{1}{10}=\frac{5+3}{30}=\frac{8}{30}=\frac{4}{15}$

Time taken by by both working together = $\frac{1}{\frac{4}{15}}=\frac{15}{4}=3.75=3\,hour\,45\,minutes$

Therefore, In 3 hour 45 minutes Both working together do all of yard work.