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4 years ago

He length of a rectangle is three times its width. The perimeter of the rectangle is at most 112 cm.

2 answers:

8 0

The equation relating length to width
L = 3W
The inequality stating the boundaries of the perimeter
LW <= 112
When you plug in what L equals in the first equation into the second equation, you get
3W * W <= 112
evaluate
3W^2 <= 112
3W <= $4 \sqrt{7}$
W <= $\frac{4 \sqrt{7} }{3}$ cm

Semenov [28]4 years ago

8 0

Answer:

the answer is 2w+2*(3w)≤112

Step-by-step explanation:

If the rectangle is three times the width and the perimeter is 112 cm then we do 2w+2*(3w)≤112 since it is bigger or the same as 112

btw the other guy is so wrong

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72 pint = ? Gallons. How much is the gallon?

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8 pints = 1 gallon
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4 years ago

The parking space shown on the right has an area of 216 ft². A custom truck has rectangular dimensions of 12.1 ft by 3.6 ft. Can

mart [117]

Answer:

• Yes, the area of the truck is less than the area of the parking space.

• The missing dimension of the parking space is 12 ft.

Explanation:

The area of the parking space = 216 ft²

Part A

The dimensions of the custom truck = 12.1 ft by 3.6 ft.

To determine if the truck can fit into the space, we calculate the area of the truck.

$\begin{gathered} \text{Area of the truck}=12.1\times3.6 \\ =43.56ft^2 \end{gathered}$

Since the area of the truck is less than the area of the parking space, the truck will fit into the space.

Part B

The parking space is in the shape of a parallelogram.

$\text{Area of a parallelogram=Base x Perpendicular Height}$

Given:

• Area = 216 ft²

• Base = b ft

• Perpendicular Height = 18 ft

We then have:

$\begin{gathered} 216=b\times18 \\ 18b=216 \\ b=\frac{216}{18} \\ b=12\text{ ft} \end{gathered}$

The missing dimension of the parking space is 12 feet.

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2 years ago

Answer any for brainliest.

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Answer:

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Step-by-step explanation:

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3 years ago

Which expression is equivalent to the area of metal sheet required to make this square-shaped traffic sign?

Lena [83]

(x+1)^2
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3 years ago

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Find the area of the shaded region. geometry please help if your good at it. will mark brainlist

AnnZ [28]

Area of shaded region = area of circle - area of segment

(where "segment" refers to the unshaded region)

Area of circle = π (11.1 m)² ≈ 387.08 m²

The area of the segment is equal to the area of the sector that contains it, less the area of an isosceles triangle:

Area of segment = area of sector - area of triangle

130° is 13/36 of a full revolution of 360°. This is to say, the area of the sector with the central angle of 130° has a total area equal to 13/36 of the total area of the circle, so

Area of sector = 13/36 π (11.1 m)² ≈ 139.78 m²

Use the law of cosines to find the length of the chord (the unknown side of the triangle, call it x) :

x ² = (11.1 m)² + (11.1 m)² - 2 (11.1 m)² cos(130°)

x ² ≈ 404.82 m²

x = 20.12 m

Call this length the base of the triangle. Use a trigonometric relation to determine the corresponding altitude/height, call it y. With a vertex angle of 130°, the two congruent base angles of the triangle each measure (180° - 130°)/2 = 25°, so

sin(25°) = y / (11.1 m)

y = (11.1 m) sin(25°)

y ≈ 4.69 m

Then

Area of triangle = xy/2 ≈ 1/2 (20.12 m) (4.69 m) ≈ 47.19 m²

so that

Area of segment ≈ 139.78 m² - 47.19 m² ≈ 92.59 m²

Finally,

Area of shaded region ≈ 387.08 m² - 92.59 m² ≈ 294.49 m²

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3 years ago