Answer:
(A) 0.297
(B) 0.595
Step-by-step explanation:
Let,
H = a person who suffered from a heart attack
G = a person has the periodontal disease.
Given:
P (G|H) = 0.79, P(G|H') = 0.33 and P (H) = 0.15
Compute the probability that a person has the periodontal disease as follows:
(A)
The probability that a person had periodontal disease, what is the probability that he or she will have a heart attack is:
Thus, the probability that a person had periodontal disease, what is the probability that he or she will have a heart attack is 0.297.
(B)
Now if the probability of a person having a heart attack is, P (H) = 0.38.
Compute the probability that a person has the periodontal disease as follows:
Compute the probability of a person having a heart attack given that he or she has the disease:
The probability of a person having a heart attack given that he or she has the disease is 0.595.
Answer:
1 like
2 unlike
3 like
4 like
5 unlike
6 unlike
Step-by-step explanation:
For terms to be like terms, they must have exactly the same variables and the same exponents.
1 like
2 unlike
3 like
4 like
5 unlike
6 unlike
5( y + 2/5) = -13
Distribute the 5 by multiplying the 5 by each term inside the set of parentheses:
5y + 2 = -13
Subtract 2 from both sides:
5y = -15
Divide both sides by 5:
Y = 3
The answer is y = 3