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3 years ago

Explain how the vapor pressure calculated and the resulting Clausius-Clapeyron plot are affected?

Chemistry

1 answer:

marta [7]3 years ago

5 0

Answer:

According to the second statement of the questions, to calculate the air pressure, the volume occupied by the air is assumed constant. This statement is not correct due to the volume that is fullfield by the air is in reality decreasing as the ethanol is added. This way, the vapor pressure calculated and resulting Clausius-Clapeyron plot are affected because as volume decreases, vapor pressure will decrease.

Explanation:

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A chemist decomposes samples of several compounds; the masses of their constituent elements are listed. Calculate the empirical

Zina [86]

Answer:

you can see the empirical formula at the pic

4 0

3 years ago

In order to complete his research project, Roger needs to make a mixture of 86 mL of a 36% acid solution from a 39% acid

Zina [86]

The volume of the 39% acid solution that Roger needs to use to make a mixture of 86 mL of a 36% acid solution is 74.27 mL.

The mixture of the acids solutions is given by:

$CV = C_{1}V_{1} + C_{2}V_{2}$ (1)

Where:

C: is the concentration if the mixture = 36%

V: is the total volume of the mixture = 86 mL

C₁: is the concentration of acid 1 = 39%

V₁: is the volume if acid 1 =?

C₂: is the concentration of acid 2 = 17%

V₂: is the volume of acid 2

The sum of V₁ and V₂ must be equal to V, so:

$V = V_{1} + V_{2}$

$V_{2} = V - V_{1}$ (2)

By entering equation (2) into (1), we have:

$CV = C_{1}V_{1} + C_{2}(V - V_{1})$

$36\%*86 mL = 39\%*V_{1} + 17\%(86 mL - V_{1})$

Changing the percent values to decimal ones:

$0.36*86 mL = 0.39*V_{1} + 0.17(86 mL - V_{1})$

Now, by solving the above equation for V₁:

$V_{1} = 74.27 mL$

Therefore, the volume of the 39% acid solution is 74.27 mL.

To learn more about mixture and solutions, go here: brainly.com/question/6358654?referrer=searchResults

I hope it helps you!

7 0

3 years ago

Read 2 more answers

The type of nuclear division that produces gametes is called

schepotkina [342]

This process is called meiosis! good luck!

8 0

3 years ago

What is the new pressure of 150 mL of a gas that is compressed to 50 mL when the original pressure was 2.0 atm and the temperatu

tatyana61 [14]

Answer:

1) 6.0 atm.

2) 2.066 atm.

Explanation:

From the general law of ideal gases:

PV = nRT.

where, P is the pressure of the gas.

V is the volume of the container.

n is the no. of moles of the gas.

R is the general gas constant.

T is the temperature of the gas (K).

1) What is the new pressure of 150 mL of a gas that is compressed to 50 mL when the original pressure was 2.0 atm and the temperature is held constant?

At constant T and at two different (P, and V):

P₁V₁ = P₂V₂.

P₁ = 2.0 atm, V₁ = 150.0 mL.

P₂ = ??? atm, V₂ = 50.0 mL.

∴ P₂ = P₁V₁/V₂ = (2.0 atm)(150.0 mL)/(50.0 mL) = 6.0 atm.

2. A sample of a gas in a rigid container at 30.0°C and 2.00 atm has its temperature increased to 40.0°C. What will be the new pressure?

Since the container is rigid, so it has constant V.

At constant V and at two different (P, and T):

P₁/T₁ = P₂/T₂.

P₁ = 2.0 atm, T₁ = 30.0°C + 273 = 303 K.

P₂ = ??? atm, T₂ = 40.0°C + 273 = 313 K.

∴ P₂ = P₁T₂/T₁ = (2.0 atm)(313.0 K)/(303.0 K) = 2.066 atm.

3 0

4 years ago

When methyloxirane is treated with HBr, the bromide ion attacks the less substituted position. However, when phenyloxirane is tr

konstantin123 [22]

Answer:

See explanation and picture below

Explanation:

First, in the case of methyloxirane (Also known as propilene oxide) the mechanism that is taking place there is something similar to a Sn2 mechanism. Although a Sn2 mechanism is a bimolecular substitution taking place in only step, the mechanism followed here is pretty similar after the first step.

In both cases, the H atom of the HBr goes to the oxygen in the molecule. You'll have a OH⁺ in both. However, in the case of methyloxirane the next step is a Sn2 mechanism step, the bromide ion will go to the less substitued carbon, because the methyl group is exerting a steric hindrance. Not a big one but it has a little effect there, that's why the bromide will rather go to the carbon with more hydrogens. and the final product is formed.

In the case of phenyloxirane, once the OH⁺ is formed, the next step is a Sn1 mechanism. In this case, the bond C - OH⁺ is opened on the side of the phenyl to stabilize the OH. This is because that carbon is more stable than the carbon with no phenyl. (A 3° carbon is more stable than a 2° carbon). Therefore, when this bond opens, the bromide will go there in the next step, and the final product is formed. See picture below for mechanism and products.

4 0

3 years ago